COMPLEX ANALYSIS: Maple Worksheets,
2009
(c) John H. Mathews Russell W. Howell
mathews@fullerton.edu howell@westmont.edu
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COMPLEX ANALYSIS: for Mathematics &
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CHAPTER 7 TAYLOR and LAURENT
SERIES
Section 7.1 Uniform
Convergence
Throughout this text we have
compared and contrasted properties of complex functions with
functions whose domain and range lie entirely within the reals. There
are many similarities, such as the standard differentiation formulas.
However, there are also some surprises, and in this chapter we will
encounter one of the hallmarks distinguishing complex functions from
their real counterparts.
It is possible for a function defined on the real numbers to be
differentiable everywhere and yet not be expressible as a power
series (see Exercise 7.2.20 at the end of Section 7.2). In the
complex case, however, things are much simpler! It turns out that if
a complex function is analytic in the disk
, its Taylor series about
will converge to the function at
every point in this disk. Thus, analytic functions are locally
nothing more than glorified polynomials.
Definition 7.1: Uniform convergence
The sequence
converges uniformly
to
on the set T if for every
, there exists a positive integer
(which depends only on
) such that if
, then
for all
.
Example 7.1, Page 262.
The sequence
=
converges uniformly to the function
on the entire complex plane because
for any
>0 ,
is satisfied for all
for
>
, where
is any integer greater than
. We leave the details for showing
this as an exercise.
There is a useful procedure known as the Weierstrass M-test that can help determine whether an infinite series is uniformly convergent.
Theorem 7.1 (Weierstrass M-test)
Suppose the infinite series
has the property that for each k,
for all
.
If
converges, then
converges uniformly on T.
Theorem 7.2 gives an interesting application of the Weierstrass M-test.
Theorem 7.2
Suppose the power series
has radius of convergence
.
Then for each
,
, the series converges uniformly on
the closed disk
.
Corollary 7.1
For each
,
, the geometric series converges
uniformly on the closed disk
.
Theorem 7.3
Suppose
is a sequence of continuous
functions defined on a set T containing the contour C. If
converges uniformly to
on the set T, then
(i)
is continuous on T, and
(ii)
=
.
Corollary 7.2
If the series
converges uniformly to
on the set T, and C is a contour
contained in T, then
=
.
Example 7.2, Page 266.
Show that
, for all
in
:
.
> f:='f': p:='p':
P:='P': s:='s': t:='t': z:='z': Z:='Z':
f := z -> log(1-z):
t := taylor(f(Z), Z=0, 11):
s := subs(Z=z,t):
p := z -> subs(Z=z,convert(t, polynom)):
`f(z) ` = f(z);
`f(z) ` = s;
P[10](z) = p(z);
![]()
![]()
Or we could use Maple's "unapply" procedure.
> f:='f': p:='p':
P:='P': s:='s': t:='t': z:='z': Z:='Z':
f := z -> log(1-z):
s := taylor(f(z), z=0, 11):
p:=unapply(convert(taylor(f(z),z=0,11),polynom),z):
`f(z) ` = f(z);
`f(z) ` = s;
P[10](z) = p(z);
![]()
![]()
Sum up the terms to verify that we
have things right.
> f:='f': n:='n':
s:='s': S:='S': z:='z':
f := z -> log(1-z):
S10 := z -> sum(-1/n*z^n, n=1..10):
S := z -> sum(-1/n*z^n, n=1..infinity):
`f(z) ` = f(z);
s[10](z),` = `,Sum(-1/n*z^n, n=1..10) = S10(z);
s[infinity](z),` = `,Sum(-1/n*z^n, n=1..infinity) =
S(z);
, ` = `, Sum(-1/n*z^n,n = 1 .. 10) = -z-1/2...](images/C07-155.gif)
, ` = `, Sum(-1/n*z^n,n = 1 .. infini...](images/C07-156.gif)
The real variable plot of
and
is:
>
plot({f(x),S10(x)},
x=-0.999..0.999, y=-3..0.7,
title=`y=ln(1-z) and y=s10(x)`,
labels=[` x`,`y `],
tickmarks=[5,7],
view=[-1..1,-3..0.7]);
![[Maple Plot]](images/C07-159.gif)
End of Section 7.1.