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for
Chapter 11 Applications of Harmonic Functions
11.1 Preliminaries
Overview
A wide variety of problems in engineering and
physics involve harmonic functions, which are the real or imaginary
part of an analytic function. The standard applications
are two dimensional steady state temperatures, electrostatics, fluid
flow and complex potentials. The techniques of conformal
mapping and integral representation can be used to construct a
harmonic function with prescribed boundary
values. Noteworthy methods include Poisson's integral
formulae; the Joukowski transformation; and Schwarz-Christoffel
transformation. Modern computer software is capable of
implemeting these complex analysis methods.
In most applications involving harmonic functions, a harmonic function that takes on prescribed values along certain contours must be found. In presenting the material in this chapter, we assume that you are familiar with the material covered in Sections 2.5, 3.3, 5.1, and 5.2. If you aren't, please review it before proceeding.
Example 11.1. Find
the function u(x,y) that is harmonic
in the vertical strip
and takes on the boundary values
for
all y, and
for
all y,
along the vertical lines
, respectively.
![[Graphics:Images/ApplicationPreliminaryMod_gr_5.gif]](applicationpreliminary/ApplicationPreliminaryMod/Images/ApplicationPreliminaryMod_gr_5.gif)
Solution. Intuition suggests that we should seek a
solution that takes on constant values along the vertical lines of
the form
and that u(x,y) be a function of
x alone; that is,
, for
and
for all y.
Laplace's equation,
, implies
that
, which
implies
, where
m and c
are constants. The stated boundary
conditions
and
lead
to the solution
.
The level curves
are
vertical lines as indicated in Figure 11.1.
![]()
Figure 11.1 Level curves of the harmonic function
.
Example 11.2. Find
the function
that is harmonic in the sector
and takes on the boundary values
for x
> 0,
for
all points on the ray
.
![[Graphics:Images/ApplicationPreliminaryMod_gr_29.gif]](applicationpreliminary/ApplicationPreliminaryMod/Images/ApplicationPreliminaryMod_gr_29.gif)
Solution. Recalling that the
function
is
harmonic and takes on constant values along rays emanating from the
origin, we see that a solution has the form
,
where a and b
are constants. The boundary conditions lead
to
.
The level curves
are
rays emanating from the origin as indicated in Figure 11.2.
![]()
Figure 11.2 Level curves of the harmonic function
.
Example 11.3. Find
the function
that is harmonic in the annulus
and
takes on the boundary values
when
, and
when
.
![[Graphics:Images/ApplicationPreliminaryMod_gr_49.gif]](applicationpreliminary/ApplicationPreliminaryMod/Images/ApplicationPreliminaryMod_gr_49.gif)
Solution. This problem is a companion to the one in
Example 11.2. Here we use the fact
that
is
a harmonic function, for all
. The
solution is
,
and the level curves
are
concentric circles, as illustrated in Figure 11.3.
![]()
Figure 11.3 Level curves of the harmonic function
.
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