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Chapter 2 Complex Functions
Overview
In Chapter 1 we developed a basic theory of complex numbers. For the next few chapters we turn our attention to functions of complex numbers. They are defined in a similar way to functions of real numbers that you studied in calculus; the only difference is that they operate on complex numbers rather than real numbers. This chapter focuses primarily on very basic functions, their representations, and properties associated with functions such as limits and continuity. You will learn some interesting applications as well as some exciting new ideas.
2.1 Functions and Linear Mappings
A complex-valued function f
of the complex variable z is a rule that assigns to each complex
number z in a set D
one and only one complex number w. We
write
and
call w the image of z
under f. A simple
example of a complex-valued function is given by the
formula
. The
set D is called the domain of
f, and the set of all
images
is
called the range of f. When
the context is obvious, we omit the phrase complex-valued, and simply
refer to a function f, or to a
complex function f.
We can define the domain to be any set
that makes sense for a given rule, so for
, we
could have the entire complex plane for the domain D,
or we might artificially restrict the domain to some set such
as
. Determining
the range for a function defined by a formula is not always easy, but
we will see plenty of examples later on. In some contexts
functions are referred to as mappings or transformations.
In Section 1.6, we used the term domain to indicate a connected open set. When speaking about the domain of a function, however, we mean only the set of points on which the function is defined. This distinction is worth noting, and context will make clear the use intended.
Just as z can be expressed by its real and
imaginary parts,
, we
write
, where
u and v
are the real and imaginary parts of w,
respectively. Doing so gives us the
representation
.
Because u and v depend on x and
y, they can be considered to be
real-valued functions of the real variables x
and y; that is,
and
.
Combining these ideas, we often write a complex function f
in the form
.
Figure 2.1 illustrates the notion of a function (mapping) using these
symbols.
![[Graphics:Images/ComplexFunLinear_gr_12.gif]](complexfunlinear/ComplexFunLinearMod/Images/ComplexFunLinear_gr_12.gif)
Figure 2.1 The mapping.
There are two methods for defining a
complex function in
Mathematica.
Exploration.
We now give several examples that illustrate how to express a complex function.
Example
2.1. Write
in
the for
.
Solution. Using the binomial formula, we obtain
![[Graphics:Images/ComplexFunLinear_gr_25.gif]](complexfunlinear/ComplexFunLinearMod/Images/ComplexFunLinear_gr_25.gif)
so that
.
Example
2.2. Express the function
in
the form
.
Solution. Using the elementary properties of complex
numbers, it follows that
![]()
so that
.
Examples 2.1 and 2.2 show how to find
u(x,y) and v(x,y)
when a rule for computing f is given. Conversely, if u(x,y)
and v(x,y) are two real-valued
functions of the real
variables x and y,
they determine a complex-valued
function
, and
we can use the formulas
and ![]()
to find a formula for f involving the variables z and
.
Example
2.3. Express
by
a formula involving the variables
.
Solution. Calculation reveals that
![[Graphics:Images/ComplexFunLinear_gr_60.gif]](complexfunlinear/ComplexFunLinearMod/Images/ComplexFunLinear_gr_60.gif)
Using
in
the expression of a complex function f may be
convenient. It gives us the polar
representation
,
where U and V
are real functions of the real variables r
and
.
Remark. For a given
function f, the functions u and v
defined above are different from those used previously
in
which
used Cartesian coordinates instead of polar coordinates.
Example
2.4. Express
in
both Cartesian and polar form.
Solution. For the Cartesian form, a simple calculation
gives
![[Graphics:Images/ComplexFunLinear_gr_73.gif]](complexfunlinear/ComplexFunLinearMod/Images/ComplexFunLinear_gr_73.gif)
so that
.
For the polar form, we get v
![[Graphics:Images/ComplexFunLinear_gr_75.gif]](complexfunlinear/ComplexFunLinearMod/Images/ComplexFunLinear_gr_75.gif)
so that
.
Remark. Once we
have defined u and v
for a function f in Cartesian form,
we must use different symbols if we want to express f
in polar form. As is clear here, the functions u
and U are quite different, as are
v and V. Of
course, if we are working only in one context, we can use any symbols
we choose.
For a given function f, the functions u and v defined here are
different from those defined by equation (2-1), because equation
(2-1) involves Cartesian coordinates and equation (2-2) involves
polar coordinates.
Example
2.5. Express
in
polar form.
Solution. We obtain
so that
.
We now look at the geometric
interpretation of a complex function. If D
is the domain of real-valued functions u(x,y)
and v(x,y), the
equations
and ![]()
describe a transformation (or mapping) from D
in the xy plane into the uv plane,
also called the w plane. Therefore,
we can also consider the function
to be a transformation (or mapping) from the set D
in the z plane onto the range R in
the w plane. This idea was
illustrated in Figure 2.1. In the following paragraphs we present
some additional key ideas. They are staples for any kind of function,
and you should memorize all the terms in bold.
If A is a
subset of the domain D of
f, the set
is
called the image of the set A, and
f is said to map A
onto B. The image of a
single point is a single point, and the image of the entire domain,
D, is the range, R. The
mapping
is
said to be from A into S
if the image of A is contained in
S. Mathematicians use the
notation
to indicate that a function maps A
into S. Figure 2.2
illustrates a function f whose domain is D
and whose range is R. The
shaded areas depict that the function maps A
onto B. The function also
maps A into R,
and, of course, it maps D onto
R.
![[Graphics:Images/ComplexFunLinear_gr_100.gif]](complexfunlinear/ComplexFunLinearMod/Images/ComplexFunLinear_gr_100.gif)
Figure 2.2maps A onto B;
maps A into R.
The inverse image of a point w
is the set of all points z in
D such that
. The
inverse image of a point may be one point, several points, or nothing
at all. If the last case occurs then the point
w is not in the range of f. For
example, if
, the
inverse image of the point
is the single point
,
because
, and
is the only point that maps to
. In
the case of
, the
inverse image of the point
is the set
. You
will learn in Section 5.1
that, if
, the
inverse image of the point 0 is the
empty set---there is no complex number z
such that
.
The inverse image of a set of points, S,
is the collection of all points in the domain that map into
S. If f maps D onto
R it is possible for the inverse
image of R to be function as well,
but the original function must have a special property: a function
f is said to be one-to-one if it maps
distinct points
onto
distinct points
. Many
times an easy way to prove that a function f
is one-to-one is to suppose
, and
from this assumption deduce that
must equal
. Thus,
is
one-to-one because if
, then
. Dividing
both sides of the last equation by
gives
. Figure
2.3 illustrates the idea of a one-to-one function: distinct points
get mapped to distinct points.
![[Graphics:Images/ComplexFunLinear_gr_125.gif]](complexfunlinear/ComplexFunLinearMod/Images/ComplexFunLinear_gr_125.gif)
Figure 2.3 A function w = f(z) that is one-to-one.
The function
is
not one-to-one because
, but
. Figure
2.4 depicts this situation: at least two different points get mapped
to the same point.
![[Graphics:Images/ComplexFunLinear_gr_129.gif]](complexfunlinear/ComplexFunLinearMod/Images/ComplexFunLinear_gr_129.gif)
Figure 2.4 A function that is not one-to-one.
In the exercises we ask you to demonstrate
that one-to-one functions give rise to inverses that are
functions. Loosely speaking, if
maps
the set A one-to-one and onto the set
B, then for each w
in B there exists exactly one point
z in A A
such that
. For
any such value of z we can take the
equation
and
"solve" for z as a function of
w. Doing so produces an
inverse function
where
the following equations hold:
Conversely, if
and
are functions that map A into
B and B
into A, respectively, and the above
hold, then f maps the set A
one-to-one and onto the set B.
Further, if f is a one-to-one mapping from
D onto T
and if A is a subset of D,
then f is a one-to-one mapping from A
onto its image B. We can
also show that, if
is
a one-to-one mapping from A onto
B and
is
a one-to-one mapping from B onto
S, then the composite
mapping
is
a one-to-one mapping from A onto
S.
We usually indicate the inverse of
by the symbol
. If
the domains of
and
are A and B
respectively, then we write
for
all
, and
for
all
.
Also, for
and
.
iff
, and
iff
.
Example
2.6. If
for
any complex number z, find
.
Solution. We can easily show f
is one-to-one and onto the entire complex plane. We solve for
z, given
, to
get
. This
result implies that
for
all complex numbers w.
Remark. Once we
have specified
for
all complex numbers w, we note that
there is nothing magical about the symbol w. We
could just as easily write
for
all complex numbers z.
We now show how to find the image B of a specified set A under a given mapping u+iv=w=f(z). The set A is usually described with an equation or inequality involving x and y. Using inverse functions, we can construct a chain of equivalent statements leading to a description of the set B in terms of an equation or an inequality involving u and v.
Example 2.7. Show
that the function
maps
the line
in
the xy plane onto the
line
in
the w plane.
Solution. Method 1: With
, we
want to describe
. We
let
and
get

where
is the notation for "if and only if." Note what this
result says:
.
The image of A under f,
therefore, is the set
.
Method 2: We write
and
note that the transformation can be given by the
equations
. Because
A is described
by
, we
can substitute
into
the equation
to
obtain
, which
we can rewrite as
. If
you use this method, be sure to pay careful attention to domains and
ranges.
We now look at some elementary
mappings. If we let
denote
a fixed complex constant, the transformation
is a one-to-one mapping of the z-plane onto the w-plane and is called
a translation. This
transformation can be visualized as a rigid translation whereby the
point z is displaced through the
vector
to
its new position
. The
inverse mapping is given by
and shows that T is a one-to-one mapping from
the z-plane onto the w-plane. The effect of a translation is depicted
in Figure 2.5.
![[Graphics:Images/ComplexFunLinear_gr_200.gif]](complexfunlinear/ComplexFunLinearMod/Images/ComplexFunLinear_gr_200.gif)
Figure 2.5 The translation.
If we let
be
a fixed real number, then for
, the
transformation
is a one-to-one mapping of the z-plane onto the w-plane and is called
a rotation. It
can be visualized as a rigid rotation whereby the
point z is rotated about the origin through an
angle
to
its new position
. If
we use polar coordinates and designate
in
the w-plane, then the inverse mapping is
.
This analysis shows that R is a one-to-one
mapping from the z-plane onto the w-plane. The effect of
rotation is depicted in Figure 2.6.
![[Graphics:Images/ComplexFunLinear_gr_209.gif]](complexfunlinear/ComplexFunLinearMod/Images/ComplexFunLinear_gr_209.gif)
Figure 2.6 The rotation.
Example 2.8. The
ellipse centered at the origin with a horizontal major axis of 4
units and vertical minor axis of 2 units can be represented by the
parametric equation
, for
.
Suppose we wanted to rotate the ellipse by an angle of
radians and shift the center of the ellipse 2 units to the right and
1 unit up. Using complex arithmetic, we can easily generate a
parametric equation r(t) that does
so:
for
. Figure
2.7 shows parametric plots of these ellipses.
![[Graphics:Images/ComplexFunLinear_gr_216.gif]](complexfunlinear/ComplexFunLinearMod/Images/ComplexFunLinear_gr_216.gif)
Figure 2.7 (a) Plot of the original
ellipse (b) Plot
of the rotated ellipse
![]()
If we let
be
a fixed positive real number, then the transformation
is a one-to-one mapping of the z-plane onto the w-plane and is called
a
magnification. If
, it
has the effect of stretching the distance between points by the
factor K. If
, then
it reduces the distance between points by the
factor K. The inverse transformation is given
by
and shows that S is a one-to-one mapping from
the z-plane onto the w-plane. The effect of magnification
is shown in Figure 2.8.

Figure 2.8 The magnification.
Finally, if we let
and
,
where
is
a positive real number, then the transformation
![]()
is a one-to-one mapping of the z-plane
onto the w-plane and is called a
linear transformation. It can
be considered as the composition of a rotation, a magnification, and
a translation. It has the effect of rotating the plane
though an angle given by
, followed
by a magnification by the factor
,
followed by a translation by the vector
. The
inverse mapping is given by
and
shows that L is a one-to-one mapping
from the z-plane onto the
w-plane.
Example 2.9. Show
that the linear transformation
maps
the right half plane
onto
the upper half plane
.
Solution. Method
1: Let
. To
describe
, we
solve
for
z to get
. We
have the following
Thus
, which
is the same as saying
.
Method 2: When we write
in
Cartesian form as
,
we see that the transformation can be given by the
equations
and
. Substituting
in
the inequality
gives
, or
, which
is the upper half-plane
.
Method 3: The effect of the
transformation
is a rotation of the plane through the angle
(when z is multiplied by
)
followed by a translation by the vector
. The
first operation yields the set
. The
second shifts this set up 1 unit,
resulting in the set
. We
illustrate this result in Figure 2.9.
![[Graphics:Images/ComplexFunLinear_gr_263.gif]](complexfunlinear/ComplexFunLinearMod/Images/ComplexFunLinear_gr_263.gif)
Figure 2.9 The linear transformation.
Translations and rotations preserve angles. First, magnifications rescale distance by a factor K, so it follows that triangles are mapped onto similar triangles, preserving angles. Then, because a linear transformation can be considered to be a composition of a rotation, a magnification, and a translation, it follows that linear transformations preserve angles. Consequently, any geometric object is mapped onto an object that is similar to the original object; hence linear transformations can be called similarity mappings.
Note. The usage of the phrase "linear transformation" in a "complex analysis course" is different than that the usage in "linear algebra courses".
Example 2.10. Show
that the image of the open disk
under
the linear transformation
is
the open disk
.
Solution. The inverse transformation
is
, so
if we designate the range of f as
B, then
![]()
![]()
![]()
Hence the disk with center
and
radius 1 is mapped one-to-one and
onto the disk with center
and
radius 5 as shown in Figure 2.10.
![[Graphics:Images/ComplexFunLinear_gr_292.gif]](complexfunlinear/ComplexFunLinearMod/Images/ComplexFunLinear_gr_292.gif)
Figure 2.10 The mapping.
Example 2.11. Show
that the image of the right half plane
under
the linear transformation
is
the half plane
.
Solution. The inverse transformation is given
by
,
which we write as
.
Substituting
into e
gives
, which
simplifies
. Figure
2.11 illustrates the mapping.
![[Graphics:Images/ComplexFunLinear_gr_321.gif]](complexfunlinear/ComplexFunLinearMod/Images/ComplexFunLinear_gr_321.gif)
Figure 2.11 The the linear transformation.
Exercises for Section 2.1. Functions and Linear Mappings
Graphics for Complex Functions
Mobius - Bilinear Transformation
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