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for
2.2 The Mappings
and ![]()
In Section
2.1 we studied linear mapping. Now we turn our attention to power
functions. For
,
we can express the function
in polar coordinates by
.
If we also use polar coordinates for
in the w -plane, we can express this mapping by the system of
equations
.
Because an argument of the product (z)(z)
is twice an argument of z, we say that f doubles angles at the
origin. Points that lie on the ray
,
are
mapped onto points that lie on the ray
,
. If
we now restrict the domain of
to the region
,
then the image of A under the mapping
can be described by the set
,
which consists of all points in the w-plane except the point w=0.
The inverse mapping of f, which we shall
denote by g, is then
,
where
. That
is
,
where
. The
function g is so important that we call special attention to it with
a formal definition.
Definition 2.1 (Principal
Square
Root
Function). The
function
, for
.
is called the principal square root function.
It is left as an exercise to show that f and g satisfy equations g(f(z))=z and f(g(w))=w, and thus are inverses of each other that map the set A one-to-one and onto the set B and the set B one-to-one and onto the set A, respectively. Figure 2.12. illustrates this relationship.
![[Graphics:Images/ComplexFunPowerRoot_gr_22.gif]](complexfunpower/ComplexFunPowerRootMod/Images/ComplexFunPowerRoot_gr_22.gif)
Figure 2.12 The
mapping
(and
).
What are the images of rectangles under
the mapping
? To
find out, we make use of the Cartesian form
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and the resulting system of equations
Example 2.12. Show
that the transformation
, usually
maps vertical and horizontal lines onto parabolas and use this fact
to find the image of the rectangle
. (a)
Find the image of the vertical line
. (b)
Find the image of the horizontal line
.
Solution. Using the above equations, we determine that
the vertical line
is
mapped onto the set of points given by the
equations
and
. If
, then
and
,
this equation represents a parabola with vertex
at
, oriented
horizontally, and opening to the
left. If
, the
set
has
precisely
when
, so
the part of the line
lying
above the x axis is mapped to the top half of the
parabola.
The horizontal line
is
mapped onto the parabola given by the equations
and
. If
, then
as before we get
,
this equation represents a parabola with vertex
at
, oriented
horizontally and opening to the
right. If
, the
part of the line
to
the right of the y axis is mapped to the top half of the parabola
because the set
has
precisely when
.
Quadrant I is mapped onto quadrants I and
II by
, so
the rectangle
is
mapped onto the region bounded by the top halves of the parabolas
given by
and
and the u axis. The
vertices
of
the rectangle are mapped onto the four points
, respectively,
as indicated in Figure 2.13.
Finally, we can easily verify that the
vertical line
is
mapped to the set
. This
is simply the set of non-positive real numbers. Similarly,
the horizontal line
is
mapped to the set
,
which is the set of non-negative real numbers.

Figure 2.13 The
transformation
.
Extra Example 1. Consider the
mapping
. Find
the image of the ray
and
circle
.
We can use knowledge of the inverse
mapping
to get further insight into how the mapping
acts on rectangles. If we let
,
then
,
and we note that the point
in
the z plane is related to the point
in the w-plane by the system of equations
Example 2.13. The
transformation
usually
maps vertical and horizontal lines onto portions of
hyperbolas.
(a) Find the image of
the vertical line
. (b) Find
the image of the horizontal line
.
Solution. Let
. The
above equations map the right half-plane given
by
(i.e.,
) onto
the region in the right half-plane satisfying
and
lying to the right of the hyperbola
. If
, the
equations
map
the upper half-plane
(i.e.,
) onto
the region in quadrant I satisfying
and
lying above the hyperbola
.
This situation is illustrated in Figure 2.14. We leave as
an exercise the investigation of what happens
when
.
![[Graphics:Images/ComplexFunPowerRoot_gr_160.gif]](complexfunpower/ComplexFunPowerRootMod/Images/ComplexFunPowerRoot_gr_160.gif)
Figure 2.14 The
mapping
and (
).
What happens to images of regions under
the mapping
for
,
where
? If
we use polar coordinates for
in
the w plane, we can represent this mapping by the system
.
This Equation indicate that the argument of f(z) is half the argument
of z and that the modulus of f(z) is the square root of the modulus
of z. Points that lie on the ray
are
mapped onto the ray
. The
image of the z plane (with the point z=0 deleted) consists of the
right half-plane Re(w)>0 together with the positive v
axis. The mapping is shown in Figure 2.15.
![[Graphics:Images/ComplexFunPowerRoot_gr_135.gif]](complexfunpower/ComplexFunPowerRootMod/Images/ComplexFunPowerRoot_gr_135.gif)
Figure 2.15 The
mapping
(and
).
Extra Example 2. Consider the
mapping
. Find
the image of the ray
and
circle
.
We can easily extend what we've done to
integer powers greater than 2. We begin by letting n be a
positive integer, considering the function
, for
, and
then expressing it in the polar coordinate form
.
If we use polar coordinates for
in the w -plane, this mapping can be given by the system of
equations
The image of the ray
,
is
the ray
,
and
the angles at the origin are increased by the factor n. The
functions
are
periodic with period
, so
f is in general an n-to-one
function; that is, n points in the
z-plane are mapped onto each non-zero
point in the w-plane.
If we now restrict the domain
of
to
the region
,
then the image of E under the
mapping
can
be described by the set
,
which consists of all points in the w-plane except the point w=0. The
inverse mapping of f, which we shall denote by g, is then
,
where
. That
is
,
where
. As
with the principle square root function, we make an analogous
definition for
roots.
Definition 2.2 (Principal
Root Function). The
function
,
for
is called the principal
root function.
We leave as an exercise to show that f and g are inverses of each other that map the set E one-to-one and onto the set F and the set F one-to-one and onto the set E, respectively. Figure 2.16 illustrates this relationship.
![[Graphics:Images/ComplexFunPowerRoot_gr_209.gif]](complexfunpower/ComplexFunPowerRootMod/Images/ComplexFunPowerRoot_gr_209.gif)
Figure 2.16 The
mapping
(and
).
Extra Example
3. Explore the mapping
.
Extra Example
4. Explore the mapping
.
Extra Example
5. Explore the mapping
.
Exercises
for Section 2.2. The
Mappings
and ![]()
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(c) 2006 John H. Mathews, Russell W. Howell