Example 27. The
conformal mapping
.
It can be constructed via the Schwarz-Christoffel
integral
,
also
.
The image of the upper half-plane
is
the semi-infinite strip
,
and the angles are
.
Remark. Hint:
Set
and
,
and the angles are
.
![[Graphics:Images/ConformalMapDictionary.3.1_gr_53.gif]](../Images/ConformalMapDictionary.3.1_gr_53.gif)
Consider the result that we saw in Example 25 and the conformal
mapping ![]()
The image of the upper half-plane
is
the portion of the upper half-plane
that
lies outside the unit circle
.
![[Graphics:../Images/ConformalMapDictionary.3.1_gr_59.gif]](../Images/ConformalMapDictionary.3.1_gr_59.gif)
Notice that the conformal mapping
is similar and will also map the upper
half-plane
onto
the portion of the upper half-plane
that
lies outside the unit circle
.
![[Graphics:../Images/ConformalMapDictionary.3.1_gr_65.gif]](../Images/ConformalMapDictionary.3.1_gr_65.gif)
Use familiar properties of the logarithm
,
which maps the upper half-plane
onto
the infinite strip
.
![[Graphics:../Images/ConformalMapDictionary.3.1_gr_70.gif]](../Images/ConformalMapDictionary.3.1_gr_70.gif)
Therefore, the desired conformal mapping is the composition
mapping
,
the image of the upper half-plane
is
the semi-infinite strip
.
![[Graphics:../Images/ConformalMapDictionary.3.1_gr_75.gif]](../Images/ConformalMapDictionary.3.1_gr_75.gif)
The
conformal mapping
.
![[Graphics:../Images/ConformalMapDictionary.3.1_gr_77.gif]](../Images/ConformalMapDictionary.3.1_gr_77.gif)
![[Graphics:../Images/ConformalMapDictionary.3.1_gr_79.gif]](../Images/ConformalMapDictionary.3.1_gr_79.gif)
Details 27.
Under Construction
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