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for
and their Riemann Sheets
Section 3.3 Harmonic Functions and their Riemann sheets
Let
be
a continuous real-valued function of the two real
variables
that
is defined on a domain
.
(Recall from Section
1.6 that a domain
is
an connected and open set of points in the complex
plane.)
The partial
differential equation
(3-26)
,
is known as Laplace's equation and is
sometimes referred to as the potential equation.
If
are
all continuous,
and if
satisfies
Laplace's
equation, then
is
called a harmonic
function.
In calculus we
might have been asked to show that polynomial functions
like
and
,
and transcendental functions like
and
,
and
and
,
are all harmonic functions. These pairs of functions are
not chosen at random, and there is an intimate relationship between
them,
they are called the conjugate "harmonic functions." It is
our goal to understand how this concept is tied in with analytic
functions.
On the practical
side, harmonic functions are important in the areas of applied
mathematics, engineering, and mathematical physics.
Harmonic functions are used to solve problems involving steady state
temperatures, two-dimensional electrostatics, and ideal fluid
flow.
In Section
11.2 we will show how complex analysis techniques are used
to solve these problems. For example, the
function
,
is harmonic in the upper half plane and takes on the boundary
values
and
.
The
harmonic function
.
Exploration
We begin with an important theorem relating analytic and harmonic functions.
Theorem
3.8. Let
be
an analytic function on a domain
. Then
both
and
are
harmonic functions on
. In
other words, the real and imaginary parts of an analytic function are
harmonic.
Proof. Since
is
differentiable on
, the
Cauchy-Riemann
equations (Theorem 3.3 in Section
3.2) imply that
and
,
and that
.
In Corollary 6.2, (see Section
6.5), we will prove that if
is
analytic on
, then
is
also analytic on
.
Since
is
differentiable on
, the
Cauchy-Riemann
equations imply that the all the second partial
derivatives:
and
,
exist are and are continuous on
.
Using these facts,
we can start with the above mentioned Cauchy Riemann equations
and take the partial derivative with respect to
of each side of these equations and obtain
and
.
Similarly, taking the partial derivative of each side with respect to
yields
and
.
Since the partial derivatives
are
all continuous,
we use a theorem from the calculus of real functions that states that
the mixed partial derivatives are equal; that is,
and
.
Combining all these results finally gives
,
and
.
Therefore both
and
are
harmonic functions on
.
Definition (Harmonic
Conjugate). If we have a
function
that
is harmonic on the domain
and
if we can find another
harmonic function
such
that the partial derivatives for
and
satisfy
the Cauchy-Riemann
equations
throughout
, then
we say that
is
a harmonic conjugate
of
.
Furthermore, it then follows that the
function
is
analytic
on
.
Theorem
3.8 unlocks the relationship among harmonic functions,
conjugate harmonic functions and analytic functions.
Specifically, it clearly states the special relationship between a
harmonic function and it's conjugate harmonic
function.
Loosely speaking, the harmonic function is the real part of the given
analytic function and the harmonic conjugate function
is the imaginary part of the given analytic function. This
concept is illustrated in Examples 3.11 and 3.12 and the Extra
Examples.
Example 3.11. Show
that
is
a harmonic function and find a conjugate harmonic
function
,
and an analytic function
.
Solution. Given
, we
have
and
the second partial
derivatives are
. It
follows that
,
hence
is
a harmonic function for all
.
If we choose
, we
have
and
the second partial
derivatives are
. It
follows that
,
hence
is
a harmonic function for all
.
Therefore, the harmonic conjugate of
,
is
.
Furthermore,
satisfy
the Cauchy-Riemann
equations
, and
.
Therefore,
is
an analytic function.
Alternative Solution.
The function
is
analytic for all values of
.
Hence, it follows from Theorem
3.8 that both
, and
,
are harmonic functions.
Example 3.12. Show
that
is
a harmonic conjugate of
.
Solution. Given
, we
have
and the second partial derivatives are
. It
follows that
,
hence
is
a harmonic function for all
.
Similarly, for
, we
have
and the second partial derivatives are
. It
follows that
,
hence
is
a harmonic function for all
.
Furthermore,
satisfy
the Cauchy-Riemann
equations
, and
.
Using Theorem
3.4, we see
that
is
an analytic
function.
Therefore, the harmonic conjugate of
,
is
.
Alternative Solution.
The function
is
analytic for all values of
.
Hence, it follows from Theorem
3.8 that both
, and
,
are harmonic functions.
Therefore, the harmonic conjugate of
,
is
.
Aside. Figures 3.2
and 3.3 show the graphs of
and
.
The partial derivatives of
are
and
,
and the partial derivatives of
are
and
.
They satisfy the
Cauchy-Riemann
equations because they are the real and imaginary parts of
an analytic function.
At the point
, we
have
and
, and
these partial derivatives appear along
the edges of the surfaces for
at
the points
and
, respectively.
Similarly, at the point
, we
have
and
and
these partial derivatives appear
along the edges of the surfaces for
at
the points
and
, respectively.
Figure
3.2 a
. Figure
3.3 a
.
Figure
3.2 b
, Figure
3.3 b
,
at
we have
.
at
we have
.
Figure
3.2 c
, Figure
3.3 c
,
at
we have
. at
we have
.
Figures 3.2 and 3.3
For
the function
we
see that
and
.
A question about the harmonic conjugate.
If
is
the harmonic conjugate of
, then
is
is
the harmonic conjugate of
?
The following example shows that this is
not the case,
and
is
not the harmonic conjugate
of
.
Extra Example
3.12.1. Given the harmonic
functions
and
,
and the analytic
function
.
3.12.1 (a) Show
that
is
not an analytic
function.
Explore Extra Solution 3.12.1 (a).
3.12.1 (b) Show
that
is
an analytic function, for all
.
Explore Extra Solution 3.12.1 (b).
We can use complex
analysis to show easily that certain combinations of harmonic
functions are harmonic. For example,
if
is
a harmonic conjugate of
, then
their product
is
a harmonic function. This can be verified directly
by computing the partial derivatives and showing that Laplace's
equation (3-26) holds, but the details
are tedious. If we use complex variable
techniques instead, we can start with the fact
that
is
an analytic
function. Then we observe that
the square of
is
also an analytic function, which is
, which
can be written as
.
We then know
immediately that the imaginary part,
, is
a harmonic function by Theorem
3.8.
Since a constant multiple of a harmonic function is harmonic, it
follows that
is
harmonic. It is left as an exercise to
show that if
and
are
two harmonic functions that are not
related in the preceding fashion, then their product
need not be harmonic.
Method I. Construction of the Harmonic Conjugate of u(x,y) using Integration.
We now introduce
methods for the construction of a harmonic conjugate
function.
The first method uses familiar techniques of calculus.
Theorem 3.9 (Construction of a
Conjugate). Let
be
harmonic in an
-neighborhood
of the point
.
Then there exists a conjugate harmonic
function
defined
in this neighborhood such that
,
is an analytic function.
Proof. A conjugate harmonic
function
will
satisfy the Cauchy-Riemann
equations
and
.
Assuming that such a function exists, we determine what it would have
to look like by using a two-step process.
First, we integrate
(which
should equal
)
with respect to
and
get
(3-27) ![[Graphics:Images/HarmonicFunctionMod_gr_713.gif]](harmonicfunction/HarmonicFunctionMod/Images/HarmonicFunctionMod_gr_713.gif)
where
is a function of
alone
that is yet to be determined. Second, we
compute
by
differentiating
both sides of this equation with respect to
and
replacing
with
on
the left side, which gives
It can be shown (we leave the details for the reader) that because u
is harmonic, all terms except those involving
in
the last equation
will cancel, revealing a formula for
involving
alone. Elementary integration of the single-variable
function
can
then be used to discover
. We
finally observe that the function
so
created indeed has the properties we seek.
The
functions
and
are
computed with the formulas:
,
and
.
Remark. If you prefer a
more succinct formula, then the harmonic conjugate
of
is
given by
.
Technically we
should always specify the domain of a function when we define
it. When no such specification is given, it is often
assumed that the domain is the entire complex plane, or the largest
set for which the expression defining the function which makes
sense.
Example 3.13. Show
that
is
a harmonic function and find the harmonic
conjugate
.
Solution. We follow the construction process of
Theorem
3.9. The first partial derivatives are
(3-28)
and
.
To verify that
is
harmonic, we compute the second partial derivatives and note
that
,
so
satisfies
Laplace's Equation
(3-26).
To construct
, we
start with Equation (3-27) and the first
of Equations (3-28) and
the Cauchy-Riemann
equation
and
get
![[Graphics:Images/HarmonicFunctionMod_gr_742.gif]](harmonicfunction/HarmonicFunctionMod/Images/HarmonicFunctionMod_gr_742.gif)
We now need to differentiate the left and right sides of this
equation with respect to
,
.
Use Equation (3-28) and the Cauchy-Riemann
equation
to
obtain
![]()
It follows easily that
,
then an easy integration yields
, where
is a real constant.
For convenience, we can choose
.
Therefore,
.
The "ghost of the imaginary numbers" - the subtle connection between Harmonic and Analytic Functions.
When you look at a
family of level curves of a real function
, do
you naturally think of complex numbers ?
Certainly, it it not the first thing that pops into our
minds. However, it seems to be subtle fact when studying
complex analysis.
We cannot fail to
stress the importance of the harmonic function pair that is
constructed with Theorem
3.8 and Theorem
3.9.
The orthogonal grid formed by the families of a harmonic functions
and how complex functions are used to find them is one goal
of this book and is discussed in detail in Chapter 11. In
reality, they are constructed with inverse
functions
.
It will take a while to feel comfortable with these concepts and that
is why they are studied later in the book.
For the time being do not worry about them, they are merely
ghosts of the imaginary
numbers.
For practical
purposes, it suffices to consider regions in the
-plane
and their image in the
-plane. However,
the concept of
a Riemann surface as being an "two dimensional manifold" has been
around for a long time. So it is no surprise that things
get sticky.
The reader can do research and see that work being done regarding
harmonic functions on Riemann surfaces (and also on
foliations).
Applications of Harmonic Functions
In Section
11.4 we will introduce the complex
potential
, which
is an analytic function and
,
are harmonic functions. It has many physical
interpretations, some of which are listed below.
![[Graphics:Images/HarmonicFunctionMod_gr_874.gif]](harmonicfunction/HarmonicFunctionMod/Images/HarmonicFunctionMod_gr_874.gif)
Interpretations
for the level curves of
and
.
We do not have time to explore all of these applications at this time. So we will introduce the topic of ideal fluid flow.
Ideal Fluid Flow
We assume that an
incompressible and frictionless fluid flows over the complex plane
and that all cross sections in planes parallel to the
complex plane are the same. Situations such as this occur
when fluid is flowing in a deep channel. The velocity
vector at the point
is
(3-29)
.
The assumption
that the flow is irrotational and has no sources or sinks implies
that both the curl and divergence vanish, that is,
(3-30)
and
.
Hence
obey
the partial differential equations
(3-30)
,
(3-30) and
.
Equations (3-30) are similar to the
Cauchy-Riemann
equations and permit us to define a special complex
function:
(3-31)
.
Here we have
(3-30)
, and
(3-30) ![]()
We can use Equations (3-30) to verify
that the Cauchy-Riemann
equations are satisfied for
:
,
and
.
Assuming the functions
have
continuous partials, Theorem
3.4 guarantees that function
defined in Equation (3-31) is analytic,
and that the fluid flow of Equation
(3-29) is the conjugate of an analytic
function, that is,
.
In Section
6.4 we will prove that every analytic
function
has
an analytic antiderivative
;
assuming this to be the case, we can write
(3-32)
,
(3-30) where
(3-30)
.
Theorem
3.8 tells us that
is
a harmonic function. If we use the vector interpretation
of a complex number we see that
the gradient of
can
be written as
.
The Cauchy-Riemann
equations applied to
give
;
making this substitution in the last equation yields
.
Equation (3-14) says
that
, which
by the preceding equation and Equation
(3-32) imply that
.
Finally, from Equation
(3-29),
is the scalar potential function for the a fluid flow, so
.
Definition. Given
the complex
potential
.
The
curves
are
called equipotentials,
and
the
curves
are
called streamlines.
They are used to describe the path of fluid flow.
In Section
11.4 we will see that the family of equipotentials is
orthogonal to the family of streamlines.
Example 3.14. Show
that the harmonic function
is
the scalar potential function for the fluid flow
.
Solution. We can write the fluid flow expression as
.
Then use the equation
.
It is easy to see that an antiderivative
of
is
.
Therefore,
is
the complex
potential
The real part of
is
the scalar potential function function:
.
Note that the hyperbolas
are
the equipotential curves,
and that the hyperbolas
are
the streamline curves,
these curves are orthogonal, as shown in Figure 3.6.
Figure
3.6 Red equipotential
curves
,
and
blue streamline curves
,
for
the complex potential
.
Optional Material for the Internet
Method II. Construction of the Harmonic Conjugate of u(x,y) using Algebra.
The usual method
proposed for finding the harmonic conjugate uses integrals and
derivatives and is shown above as Method I.
A second method discovered by the British mathematician Louis
Melville Milne-Thomson (1891-1974) uses novel algebraic
construction.
His method appears in the article On
the Relation of an Analytic Function of z to Its Real and Imaginary
Parts, L. M.
Milne-Thomson,
The Mathematical Gazette, Vol. 21, No. 244 (July 1937), pp. 228-229,
Jstor. A good reference to read is the recent article,
Recovering
Holomorphic Functions from Their Real or Imaginary Parts without the
Cauchy-Riemann Equations, William T. Shaw,
SIAM Review, Vol 46, No. 4, 2004, pp 717-718, Jstor.
The Milne-Thomson Method for constructing
a harmonic conjugate.
(i) Given the harmonic
function
then
construct
.
Under the proper conditions,
is
a harmonic conjugate of
, and
is an analytic function.
(ii) Given the
harmonic function
then
construct
.
Under the proper conditions,
is
a harmonic conjugate of
, and
is an analytic function.
Limitations of the Milne-Thomson Method.
Observe that in Milne-Thomson method, the
term
will
be transformed into
![[Graphics:Images/HarmonicFunctionMod_gr_1018.gif]](harmonicfunction/HarmonicFunctionMod/Images/HarmonicFunctionMod_gr_1018.gif)
and that the term
will be transformed into
Hence the method does not work if the given harmonic function
contains a term that is the real or imaginary part of
![]()
Hence it is applicable when the analytic function is a power series
centered about the origin.
The reader is encouraged to investigate the origins and limitations
of the Milne-Thomson method.
Extra Example
1. Use Methods I and II to construct the
harmonic conjugate of
.
Also, show that the underlying analytic function
is
.
The
orthogonal grid in the
-plane
and it's image under the analytic
function
.
Extra Example
2. Use Methods I and II to construct the
harmonic conjugate of
.
Also, show that the underlying analytic function
is
.
The
orthogonal grid in the
-plane
and it's image under the analytic
function
.
Extra Example
3. Use Methods I and II to construct the
harmonic conjugate of
.
Also, show that the underlying analytic function
is
.
The
orthogonal grid in the
-plane
and it's image under the analytic
function
.
Extra Example
4. Use Methods I and II to construct the
harmonic conjugate of
.
Also, show that the underlying analytic function
is
.
The
orthogonal grid in the
-plane
and it's image under the analytic
function
.
Extra Example
5. Use Methods I and II to construct the
harmonic conjugate of
.
Also, show that the underlying analytic function
is
.
The
orthogonal grid in the
-plane
and it's image under the analytic
function
.
Remark. There
are infinitely many branches of the multi-valued inverse
function
,
and
when the regions are combined, they will fill up the
-plane.
Extra Example
6. Use Methods I and II to construct the
harmonic conjugate of
.
Also, show that the underlying analytic function
is
.
The
orthogonal grid in the
-plane
and it's image under the analytic
function
.
Remark. There
are infinitely many branches of the multi-valued inverse
function
,
and
when the regions are combined, they will fill up the
-plane.
Tutorial Exercises for Section 3.3. Harmonic Functions
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This material is coordinated with our book Complex Analysis for Mathematics and Engineering.
(c) 2012 John H. Mathews, Russell W. Howell