Exercise 5.  Let   [Graphics:Images/AnalyticFunctionModHome_gr_125.gif]   be a polynomial of degree  [Graphics:Images/AnalyticFunctionModHome_gr_126.gif].  

5 (a).  Show that  [Graphics:Images/AnalyticFunctionModHome_gr_127.gif].  

Solution 5 (a).

See text and/or instructor's solution manual.

Solution.  Proof by mathematical induction.  

The result is clearly true when n=1.  

Assume for some  [Graphics:../Images/AnalyticFunctionModHome_gr_128.gif]  that  [Graphics:../Images/AnalyticFunctionModHome_gr_129.gif].  

Consider   [Graphics:../Images/AnalyticFunctionModHome_gr_130.gif].  

Since the derivative of the sum of two terms is the sum of the derivatives, we have  

                    [Graphics:../Images/AnalyticFunctionModHome_gr_131.gif]  

The induction assumption now gives the required result.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell