Solution 1 (a).
See text and/or instructor's solution manual.
Solution. Factor the denominator to see
that
.
The integrand
is
analytic everywhere except at the points
which
lie outside the contour
.
Hence, by the Cauchy-Goursat
Theorem we have
.
![[Graphics:../Images/CauchyGoursatModHome_gr_10.gif]](../Images/CauchyGoursatModHome_gr_10.gif)
The
points
and
which
lie outside the contour
.
We are done.
Aside. We can let Mathematica double check our work.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell