Solution 3.

See text and/or instructor's solution manual.

Solution.  Using the quadratic formula Quadratic Formula in Section 1.5,  [Graphics:../Images/CauchyGoursatModHome_gr_65.gif]  to get  

                    [Graphics:../Images/CauchyGoursatModHome_gr_66.gif]  

Since both these points  [Graphics:../Images/CauchyGoursatModHome_gr_67.gif]  lie outside [Graphics:../Images/CauchyGoursatModHome_gr_68.gif], the function  [Graphics:../Images/CauchyGoursatModHome_gr_69.gif]  is analytic inside and on  [Graphics:../Images/CauchyGoursatModHome_gr_70.gif],

hence   [Graphics:../Images/CauchyGoursatModHome_gr_71.gif]   by the Cauchy-Goursat Theorem.

                              [Graphics:../Images/CauchyGoursatModHome_gr_72.gif]

                    The points  [Graphics:../Images/CauchyGoursatModHome_gr_73.gif]  and  [Graphics:../Images/CauchyGoursatModHome_gr_74.gif]  which lie outside the contour  [Graphics:../Images/CauchyGoursatModHome_gr_75.gif].

We are done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/CauchyGoursatModHome_gr_76.gif]

[Graphics:../Images/CauchyGoursatModHome_gr_77.gif]


































This solution is complements of the authors.































 

(c) 2008 John H. Mathews, Russell W. Howell