Example 3.6. Show
that the function defined by
is not differentiable at the point
even though the Cauchy-Riemann equations are satisfied at
.
Explore Solution 3.6.
![[Graphics:../Images/CauchyRiemannMod_gr_131.gif]](../Images/CauchyRiemannMod_gr_131.gif)
Thus the Cauchy-Riemann equations hold at the origin.
![[Graphics:../Images/CauchyRiemannMod_gr_132.gif]](../Images/CauchyRiemannMod_gr_132.gif)
![[Graphics:../Images/CauchyRiemannMod_gr_133.gif]](../Images/CauchyRiemannMod_gr_133.gif)
The two limits are distinct, so f
is not differentiable at the origin.
We are done!
Aside. We can also
explore another solution.
Enter the function f[z].
![[Graphics:../Images/CauchyRiemannMod_gr_135.gif]](../Images/CauchyRiemannMod_gr_135.gif)
Find the real and imaginary parts of f[z].
![[Graphics:../Images/CauchyRiemannMod_gr_137.gif]](../Images/CauchyRiemannMod_gr_137.gif)
Determine where the Cauchy-Riemann equations hold.
![[Graphics:../Images/CauchyRiemannMod_gr_139.gif]](../Images/CauchyRiemannMod_gr_139.gif)
These equations are simultaneously zero, only when
both
which
appears to be only when
or
at the origin. But since they are not defined at the
point
,
we must use limits to complete our investigation.
Let's check to see if the Cauchy-Riemann equations hold at
.
![[Graphics:../Images/CauchyRiemannMod_gr_145.gif]](../Images/CauchyRiemannMod_gr_145.gif)
We have shown that
,
that is, the Cauchy-Riemann equations do hold at the origin.
But, f(z) is not
differentiable at
because the following two limits are distinct.
![[Graphics:../Images/CauchyRiemannMod_gr_148.gif]](../Images/CauchyRiemannMod_gr_148.gif)
![[Graphics:../Images/CauchyRiemannMod_gr_149.gif]](../Images/CauchyRiemannMod_gr_149.gif)
The two limits are distinct, so we have shown
that
is
not differentiable at the point
even though the Cauchy-Riemann equations are satisfied at
.