Exercise 1. Use the Cauchy Riemann conditions to determine where the following functions are differentiable, and evaluate the derivatives at those points where they exist.
1 (c).
.
Solution 1 (c).
See text and/or instructor's solution manual.
Answer.
, and
.
The partials are continuous everywhere,
so
for
all z.
Solution.
, and
,
so
that
,
,
,
.
The Cauchy Riemann equations are
,
,
and equality holds for all z.
The partials are continuous everywhere, so
,
for all z.
We are done.
Remark. This agrees with
the rule for differentiation that were given in Section
3.1.
It is easily seen that if we set
, then
we have
.
Hence, by the differentiation rules for
we
get
.
which can be written as
.
As we anticipated, this agrees with the Cauchy-Riemann method.
We are really done.
Aside. Recall the
identities
and
that
were used in Section
2.1.
They can be substituted in
, and
the result is
This is an alternate way to obtain the formula
. Then
calculate
.
We are really really done.
Aside. We can let Mathematica double check our work.
![[Graphics:../Images/CauchyRiemannModHome_gr_100.gif]](../Images/CauchyRiemannModHome_gr_100.gif)
maps
this orthogonal grid onto an orthogonal grid.
We
will study this phenomenon in detail in Section
10.1 and Section
11.4.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell