Exercise 16.  The complex form of the Cauchy-Riemann equations.

Recall that, for  [Graphics:Images/CauchyRiemannModHome_gr_737.gif],  we have the substitutions   [Graphics:Images/CauchyRiemannModHome_gr_738.gif]  and  [Graphics:Images/CauchyRiemannModHome_gr_739.gif].  

16 (a).  Temporarily, think of  [Graphics:Images/CauchyRiemannModHome_gr_740.gif]  as dummy symbols for variables.  

With this perspective, x and y can be viewed as functions of z and [Graphics:Images/CauchyRiemannModHome_gr_741.gif].  

Use the chain rule for a function  [Graphics:Images/CauchyRiemannModHome_gr_742.gif]  of two variables to show that

                    [Graphics:Images/CauchyRiemannModHome_gr_743.gif].

Solution 16 (a).

See text and/or instructor's solution manual.

Solution.  For  [Graphics:../Images/CauchyRiemannModHome_gr_744.gif],   [Graphics:../Images/CauchyRiemannModHome_gr_745.gif]   and   [Graphics:../Images/CauchyRiemannModHome_gr_746.gif],   we have  

                    [Graphics:../Images/CauchyRiemannModHome_gr_747.gif],    [Graphics:../Images/CauchyRiemannModHome_gr_748.gif][Graphics:../Images/CauchyRiemannModHome_gr_749.gif],    [Graphics:../Images/CauchyRiemannModHome_gr_750.gif],   and   [Graphics:../Images/CauchyRiemannModHome_gr_751.gif].   

Therefore,  

                    [Graphics:../Images/CauchyRiemannModHome_gr_752.gif]

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell