Exercise 16. The complex form of the Cauchy-Riemann equations.
Recall that, for
, we
have the substitutions
and
.
16
(a). Temporarily, think
of
as
dummy symbols for variables.
With this perspective, x and y can be viewed as functions of z and
.
Use the chain rule for a function
of
two variables to show that
.
Solution 16 (a).
See text and/or instructor's solution manual.
Solution. For
,
and
, we
have
, ![]()
,
, and
.
Therefore,
![[Graphics:../Images/CauchyRiemannModHome_gr_752.gif]](../Images/CauchyRiemannModHome_gr_752.gif)
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell