Exercise 1. Use the Cauchy Riemann conditions to determine where the following functions are differentiable, and evaluate the derivatives at those points where they exist.
1 (e).
.
Solution 1 (e).
See text and/or instructor's solution manual.
Answer.
is
differentiable only at the point
, and
.
Solution.
, and
,
so
that
,
,
,
.
The Cauchy Riemann relations are
,
,
which hold when
, which
occurs only at the point
.
The partials are continuous everywhere, so at the
point
we
find that
.
Caveat. It would be
false to use the
formula
for
values other than
.
We are done.
Aside. A reason why
f(z) is not analytic is given in
Exercise 16.
Loosely speaking, if f(z)
is analytic then there cannot be any occurrence of the
variable
.
Recall the identities
and
that
were used in Section
2.1.
They can be substituted in
, and
the result is
So technically there are "hidden" terms
involving
in
the formula for f(z), and
this precludes the possibility that f(z) can
be analytic.
Indeed, the complex form of the Cauchy-Riemann equations fails to
hold because
.
We are really done.
Aside. We can let Mathematica double check our work.
![[Graphics:../Images/CauchyRiemannModHome_gr_164.gif]](../Images/CauchyRiemannModHome_gr_164.gif)
The
image of this orthogonal grid under
is
by luck an orthogonal grid.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell