Exercise 5.  Find all the roots in both polar and Cartesian form for each expression.

5 (e).  [Graphics:Images/ComplexAlgebraRevisitedModHome_gr_223.gif].  

Solution 5 (e).

See text and/or instructor's solution manual.

Given  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_224.gif].  Then  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_225.gif]  where  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_226.gif],  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_227.gif]  and,  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_228.gif].

The primitive fourth root of unity is  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_229.gif],  
and the fourth roots of unity are  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_230.gif].  

The principal fourth root is  

        [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_231.gif]  

Thus, the fourth roots of  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_232.gif]  are  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_233.gif] which can be written as  

        [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_234.gif]  

                

                     [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_235.gif]

  

                    [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_236.gif]  for  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_237.gif].

We are done.   

The fourth roots of  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_238.gif]  can be calculated in the ordinary way.

[Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_239.gif][Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_240.gif]

[Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_241.gif][Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_242.gif]

[Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_243.gif][Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_244.gif]

[Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_245.gif][Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_246.gif]

We are done.   

Remark.  The traditional answers for the fourth roots of  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_247.gif]  are

         [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_248.gif]   for [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_249.gif].

We are done.   

Aside.  We can let Mathematica double check our work.

The principal value is

[Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_250.gif]
[Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_251.gif]
[Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_252.gif]

The other values are  

[Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_253.gif]
[Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_254.gif]
[Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_255.gif]
[Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_256.gif]

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 



This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell