Exercise 9.  Find the three solutions to  [Graphics:Images/ComplexAlgebraRevisitedModHome_gr_288.gif].  

Solution 9.

See text and/or instructor's solution manual.

Given  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_289.gif],  we can square both sides to obtain the equation  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_290.gif].  

Use  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_291.gif].  Then  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_292.gif]  where  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_293.gif],  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_294.gif],  and  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_295.gif].  

The primitive cube root of unity is  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_296.gif],  
and the cube roots of unity are  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_297.gif][Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_298.gif].  

The principal cube root of  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_299.gif]  is  

        [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_300.gif]  

Thus, the cube roots of   [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_301.gif]  are  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_302.gif]  which can be written as  

        [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_303.gif]  

                

                     [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_304.gif]

  

                    [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_305.gif]  for  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_306.gif].

We are done.   

The cube roots of  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_307.gif]  can be calculated in the ordinary way.

        [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_308.gif]  

        [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_309.gif]  

        [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_310.gif]  

Remark.  The traditional answers for the solutions to  [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_311.gif]  are

        [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_312.gif],   [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_313.gif],   [Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_314.gif].  

We are done.   

Aside.  We can let Mathematica double check our work.

The principal value is

[Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_315.gif]
[Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_316.gif]
[Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_317.gif]
[Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_318.gif]
[Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_319.gif]

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 



This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell