Exercise 9. Find
the three solutions to
.
Solution 9.
See text and/or instructor's solution manual.
Given
, we
can square both sides to obtain the equation
.
Use
. Then
where
,
, and
.
The primitive cube root of unity is
,
and the cube roots of unity are ![]()
.
The principal cube root of
is
Thus, the cube roots of
are
which
can be written as
![[Graphics:../Images/ComplexAlgebraRevisitedModHome_gr_304.gif]](../Images/ComplexAlgebraRevisitedModHome_gr_304.gif)
for
.
We are done.
The cube roots of
can
be calculated in the ordinary way.
Remark. The
traditional answers for the solutions to
are
,
,
.
We are done.
Aside. We can let Mathematica double check our work.
The principal value is
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell