Exercise 9.  For  [Graphics:Images/ComplexFunLimitModHome_gr_359.gif],  let   [Graphics:Images/ComplexFunLimitModHome_gr_360.gif].  Does  [Graphics:Images/ComplexFunLimitModHome_gr_361.gif]  have a limit as  [Graphics:Images/ComplexFunLimitModHome_gr_362.gif]?  

Solution 9.

See text and/or instructor's solution manual.

Answer.  No.  To see why, approach 0 along the real and imaginary axes respectively.

Solution.  [Graphics:../Images/ComplexFunLimitModHome_gr_363.gif]

Along the real axis we have  [Graphics:../Images/ComplexFunLimitModHome_gr_364.gif],  and

        [Graphics:../Images/ComplexFunLimitModHome_gr_365.gif]  

Along the imaginary axis we have  [Graphics:../Images/ComplexFunLimitModHome_gr_366.gif],  and

        [Graphics:../Images/ComplexFunLimitModHome_gr_367.gif]  

Since the limits along the real and imaginary axes are different, we conclude that [Graphics:../Images/ComplexFunLimitModHome_gr_368.gif] does not exist.

Aside.  Along the line  [Graphics:../Images/ComplexFunLimitModHome_gr_369.gif]  we have  [Graphics:../Images/ComplexFunLimitModHome_gr_370.gif],   

and  [Graphics:../Images/ComplexFunLimitModHome_gr_371.gif][Graphics:../Images/ComplexFunLimitModHome_gr_372.gif].   So that different "limits" are obtained along different lines to the origin.  

We are done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ComplexFunLimitModHome_gr_373.gif]

[Graphics:../Images/ComplexFunLimitModHome_gr_374.gif]

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 



This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell