Exercise 15.  Let  [Graphics:Images/ComplexFunLimitModHome_gr_460.gif]   Is  [Graphics:Images/ComplexFunLimitModHome_gr_461.gif]  continuous at the origin?  

Solution 15.

See text and/or instructor's solution manual.

Answer.  No.  The limit does not exist.   Show why.

Solution.  We can compute the limits along the x-axis and y-axis and compare them.

The limit along the positive x-axis is:  

        [Graphics:../Images/ComplexFunLimitModHome_gr_462.gif].  


The limit along the negative x-axis is:  

        [Graphics:../Images/ComplexFunLimitModHome_gr_463.gif].  
        
The limit along the y-axis is:

        [Graphics:../Images/ComplexFunLimitModHome_gr_464.gif].  

Since these limits are different, we conclude that  [Graphics:../Images/ComplexFunLimitModHome_gr_465.gif]  is not continuous at  [Graphics:../Images/ComplexFunLimitModHome_gr_466.gif].   

We remark that the function can be written as:

        [Graphics:../Images/ComplexFunLimitModHome_gr_467.gif][Graphics:../Images/ComplexFunLimitModHome_gr_468.gif].  

We are done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ComplexFunLimitModHome_gr_469.gif]

[Graphics:../Images/ComplexFunLimitModHome_gr_470.gif]


[Graphics:../Images/ComplexFunLimitModHome_gr_471.gif]

[Graphics:../Images/ComplexFunLimitModHome_gr_472.gif]


[Graphics:../Images/ComplexFunLimitModHome_gr_473.gif]

[Graphics:../Images/ComplexFunLimitModHome_gr_474.gif]

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 



This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell