Exercise 21.  Let    be continuous for all values of  z.  

21 (a).  Show that    is continuous for all  z.  

Solution 21 (a).

See text and/or instructor's solution manual.

Solution.  We have remarked that Example 2.16 shows that the function    is continuous for all  z.  

Since    is continuous for all  z,  we can apply Theorem 2.4 to the function    to conclude that    is continuous for all  z.  

This solution is complements of the authors.

(c) 2008 John H. Mathews, Russell W. Howell