Exercise
9. Construct a branch of
that
is analytic at the point
and
takes on the value
there.
Solution 9.
See text and/or instructor's solution manual.
Answer. According to equation
(5-20),
,
has
.
Solution. Let
, where
, and
.
Use equation
(5-20),
, where
, and
.
For
and
, and
we
have
and
, i.
e.
.
Then ![]()
.
We are done.
Aside. We can let Mathematica double check our work.
![[Graphics:../Images/ComplexFunLogarithmModHome_gr_942.gif]](../Images/ComplexFunLogarithmModHome_gr_942.gif)
The
mapping
where
the image of
is
.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell