Exercise 13.  Find specific values of  [Graphics:Images/ComplexFunLogarithmModHome_gr_1145.gif]  so that   [Graphics:Images/ComplexFunLogarithmModHome_gr_1146.gif].  

Solution 13.

See text and/or instructor's solution manual.

Answer.  There are many possibilities, such as  [Graphics:../Images/ComplexFunLogarithmModHome_gr_1147.gif] and  [Graphics:../Images/ComplexFunLogarithmModHome_gr_1148.gif].  Explain.

Solution.   

There are many possible counter examples.  For the choice  [Graphics:../Images/ComplexFunLogarithmModHome_gr_1149.gif] and  [Graphics:../Images/ComplexFunLogarithmModHome_gr_1150.gif]  we have

                     [Graphics:../Images/ComplexFunLogarithmModHome_gr_1151.gif],  

                     [Graphics:../Images/ComplexFunLogarithmModHome_gr_1152.gif],  

                     [Graphics:../Images/ComplexFunLogarithmModHome_gr_1153.gif].  

Hence,  [Graphics:../Images/ComplexFunLogarithmModHome_gr_1154.gif][Graphics:../Images/ComplexFunLogarithmModHome_gr_1155.gif],  

and here we have  [Graphics:../Images/ComplexFunLogarithmModHome_gr_1156.gif].  

We are done.   

Aside.  We can let Mathematica check our work.

[Graphics:../Images/ComplexFunLogarithmModHome_gr_1157.gif]

[Graphics:../Images/ComplexFunLogarithmModHome_gr_1158.gif]

We are really done.   

Another solution.  There are many possible counter examples.  For the choice  [Graphics:../Images/ComplexFunLogarithmModHome_gr_1159.gif] and  [Graphics:../Images/ComplexFunLogarithmModHome_gr_1160.gif]  we have

                    [Graphics:../Images/ComplexFunLogarithmModHome_gr_1161.gif],  

                    [Graphics:../Images/ComplexFunLogarithmModHome_gr_1162.gif],  

                    [Graphics:../Images/ComplexFunLogarithmModHome_gr_1163.gif].  

Hence,  [Graphics:../Images/ComplexFunLogarithmModHome_gr_1164.gif][Graphics:../Images/ComplexFunLogarithmModHome_gr_1165.gif],  

and here we have  [Graphics:../Images/ComplexFunLogarithmModHome_gr_1166.gif].  

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ComplexFunLogarithmModHome_gr_1167.gif]

[Graphics:../Images/ComplexFunLogarithmModHome_gr_1168.gif]

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 



This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell