Example
2.24. Consider the
mapping
.
(a) Find the images of
the vertical lines x =
a. (b) Find
the images the horizontal lines y = b.
Explore Solution 2.24.
(a) First, find the images of the vertical lines x = a.
![[Graphics:../Images/ComplexFunReciprocalMod_gr_168.gif]](../Images/ComplexFunReciprocalMod_gr_168.gif)
The image of the vertical lines x = a is the
circle
, with
center
and
radius
.
(b) Second, find the
images the horizontal lines y = b.
![[Graphics:../Images/ComplexFunReciprocalMod_gr_173.gif]](../Images/ComplexFunReciprocalMod_gr_173.gif)
The image is the circle
, with
center
and
radius
.
Now prepare some horizontal and vertical lines in Mathematica
for graphing.
Now prepare the image circles in Mathematica for graphing.
Graph the horizontal and vertical lines and their images.
![[Graphics:../Images/ComplexFunReciprocalMod_gr_180.gif]](../Images/ComplexFunReciprocalMod_gr_180.gif)
![]()
![[Graphics:../Images/ComplexFunReciprocalMod_gr_182.gif]](../Images/ComplexFunReciprocalMod_gr_182.gif)
![[Graphics:../Images/ComplexFunReciprocalMod_gr_183.gif]](../Images/ComplexFunReciprocalMod_gr_183.gif)
We see that the images of the vertical lines x =
a and horizontal lines y =
b under the mapping
are circles.
(c) 2006 John H. Mathews, Russell W. Howell