Exercise 11.  Find the image of the disk  [Graphics:Images/ComplexFunReciprocalModHome_gr_461.gif]  under  [Graphics:Images/ComplexFunReciprocalModHome_gr_462.gif].  

Make sketches of the domain set and range set.

Hint.  Consider the points  [Graphics:Images/ComplexFunReciprocalModHome_gr_463.gif]  in the z-plane and their images [Graphics:Images/ComplexFunReciprocalModHome_gr_464.gif] in the w-plane.

Solution 11.

See text and/or instructor's solution manual.

Answer.  The region that lies exterior to the unit circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_465.gif],  i.e.   [Graphics:../Images/ComplexFunReciprocalModHome_gr_466.gif].

Solution using algebra.

      The inverse mapping is  [Graphics:../Images/ComplexFunReciprocalModHome_gr_467.gif][Graphics:../Images/ComplexFunReciprocalModHome_gr_468.gif].   

Now use the substitution  [Graphics:../Images/ComplexFunReciprocalModHome_gr_469.gif]  and get:

        [Graphics:../Images/ComplexFunReciprocalModHome_gr_470.gif]  

This is the region that lies exterior to the unit circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_471.gif],  

i.e.  the image region is  [Graphics:../Images/ComplexFunReciprocalModHome_gr_472.gif].

We are done.   

                    

              [Graphics:../Images/ComplexFunReciprocalModHome_gr_473.gif]            [Graphics:../Images/ComplexFunReciprocalModHome_gr_474.gif]

  

                    The disk  [Graphics:../Images/ComplexFunReciprocalModHome_gr_475.gif]  and the image region  [Graphics:../Images/ComplexFunReciprocalModHome_gr_476.gif].

                    The points  [Graphics:../Images/ComplexFunReciprocalModHome_gr_477.gif]  and  [Graphics:../Images/ComplexFunReciprocalModHome_gr_478.gif].

Solution using point images.  

      The points  [Graphics:../Images/ComplexFunReciprocalModHome_gr_479.gif]  lie on the circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_480.gif]  in the z-plane.

The image points [Graphics:../Images/ComplexFunReciprocalModHome_gr_481.gif] lie on the circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_482.gif]  in the w-plane,

and this is shown by observing that the center of the circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_483.gif]  is  [Graphics:../Images/ComplexFunReciprocalModHome_gr_484.gif],  and then making the computations:  

        [Graphics:../Images/ComplexFunReciprocalModHome_gr_485.gif],  

        [Graphics:../Images/ComplexFunReciprocalModHome_gr_486.gif],  and  

        [Graphics:../Images/ComplexFunReciprocalModHome_gr_487.gif].

This verifies our claim that the image of the circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_488.gif]  is the circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_489.gif].  

Furthermore, we observe that the point  [Graphics:../Images/ComplexFunReciprocalModHome_gr_490.gif]  is mapped onto the point  [Graphics:../Images/ComplexFunReciprocalModHome_gr_491.gif]   so the image region lies outside the circle [Graphics:../Images/ComplexFunReciprocalModHome_gr_492.gif].

Therefore, the image of the disk  [Graphics:../Images/ComplexFunReciprocalModHome_gr_493.gif]  is the region  [Graphics:../Images/ComplexFunReciprocalModHome_gr_494.gif].

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ComplexFunReciprocalModHome_gr_495.gif]

          

              [Graphics:../Images/ComplexFunReciprocalModHome_gr_496.gif]            [Graphics:../Images/ComplexFunReciprocalModHome_gr_497.gif]

  

                    The disk  [Graphics:../Images/ComplexFunReciprocalModHome_gr_498.gif]  and the image region  [Graphics:../Images/ComplexFunReciprocalModHome_gr_499.gif].

                    The points  [Graphics:../Images/ComplexFunReciprocalModHome_gr_500.gif]  and  [Graphics:../Images/ComplexFunReciprocalModHome_gr_501.gif].

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell