Exercise 17.  Show that the transformation  [Graphics:Images/ComplexFunReciprocalModHome_gr_778.gif]  maps the disk  [Graphics:Images/ComplexFunReciprocalModHome_gr_779.gif]  onto the right half-plane  [Graphics:Images/ComplexFunReciprocalModHome_gr_780.gif].  

Make sketches of the domain set and range set.

Hint.  Consider the points  [Graphics:Images/ComplexFunReciprocalModHome_gr_781.gif]  in the z-plane and their images [Graphics:Images/ComplexFunReciprocalModHome_gr_782.gif]  in the w-plane.

Solution 17.

See text and/or instructor's solution manual.

Solution using algebra.

      The map  [Graphics:../Images/ComplexFunReciprocalModHome_gr_783.gif]   has the inverse  [Graphics:../Images/ComplexFunReciprocalModHome_gr_784.gif].   Substitute  [Graphics:../Images/ComplexFunReciprocalModHome_gr_785.gif]  into  [Graphics:../Images/ComplexFunReciprocalModHome_gr_786.gif]  and get:

        [Graphics:../Images/ComplexFunReciprocalModHome_gr_787.gif]   

Therefore, the image of   [Graphics:../Images/ComplexFunReciprocalModHome_gr_788.gif]  under  [Graphics:../Images/ComplexFunReciprocalModHome_gr_789.gif]  is the right half-plane  [Graphics:../Images/ComplexFunReciprocalModHome_gr_790.gif].  

We are done.   

          

              [Graphics:../Images/ComplexFunReciprocalModHome_gr_791.gif]            [Graphics:../Images/ComplexFunReciprocalModHome_gr_792.gif]

  

                    The disk  [Graphics:../Images/ComplexFunReciprocalModHome_gr_793.gif]  and the image right half-plane  [Graphics:../Images/ComplexFunReciprocalModHome_gr_794.gif].  

                    The points  [Graphics:../Images/ComplexFunReciprocalModHome_gr_795.gif]  and  [Graphics:../Images/ComplexFunReciprocalModHome_gr_796.gif].

Solution using point images.  

      The points  [Graphics:../Images/ComplexFunReciprocalModHome_gr_797.gif]  lie on the circle [Graphics:../Images/ComplexFunReciprocalModHome_gr_798.gif]  in the z-plane.  

Observe that their image points are  [Graphics:../Images/ComplexFunReciprocalModHome_gr_799.gif],  and these three points  [Graphics:../Images/ComplexFunReciprocalModHome_gr_800.gif]  

determine the vertical line  [Graphics:../Images/ComplexFunReciprocalModHome_gr_801.gif]  in the w-plane.  

An easy calculation shows that  [Graphics:../Images/ComplexFunReciprocalModHome_gr_802.gif],  [Graphics:../Images/ComplexFunReciprocalModHome_gr_803.gif],  [Graphics:../Images/ComplexFunReciprocalModHome_gr_804.gif]  and we have verified this observation.  

This verifies our claim that the image of the circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_805.gif]  is the vertical line  [Graphics:../Images/ComplexFunReciprocalModHome_gr_806.gif]  in the w-plane.  

Furthermore, we observe that the point  [Graphics:../Images/ComplexFunReciprocalModHome_gr_807.gif]  is mapped onto the point  [Graphics:../Images/ComplexFunReciprocalModHome_gr_808.gif]   so the image region lies to the right of  [Graphics:../Images/ComplexFunReciprocalModHome_gr_809.gif]  in the w-plane.  

Therefore, the image of the disk  [Graphics:../Images/ComplexFunReciprocalModHome_gr_810.gif]  is the right half-plane  [Graphics:../Images/ComplexFunReciprocalModHome_gr_811.gif].  

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ComplexFunReciprocalModHome_gr_812.gif]

          

              [Graphics:../Images/ComplexFunReciprocalModHome_gr_813.gif]            [Graphics:../Images/ComplexFunReciprocalModHome_gr_814.gif]

  

                    The disk  [Graphics:../Images/ComplexFunReciprocalModHome_gr_815.gif]  and the image right half-plane  [Graphics:../Images/ComplexFunReciprocalModHome_gr_816.gif].  

                    The points  [Graphics:../Images/ComplexFunReciprocalModHome_gr_817.gif]  and  [Graphics:../Images/ComplexFunReciprocalModHome_gr_818.gif].

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell