Exercise 20. Show
that
is
mapped onto the point
on
the Riemann sphere.
Solution 20.
See text and/or instructor's solution manual.
Solution. The cartesian form of the
point
in
three dimensional space is
.
The Riemann sphere sphere is centered at
and
has radius
.
If we use the notation
for
an arbitrary point in three dimensional space
then the equation of the Riemann sphere is
.
The line segment L from the
north pole
to the point
. is
given by the vector function
![]()
and we must find the point
where
L intersects the Riemann sphere. The coordinate functions
for
are
.
Substitute these values into
and
get:
Now substitute
into
and
get
.
Therefore,
.
We are done.
Aside. The lower
half of the Riemann sphere corresponds to the unit
disk
and
the upper half of the Riemann sphere corresponds to the exterior of
the unit circle
,
i. e. the region
.
![[Graphics:../Images/ComplexFunReciprocalModHome_gr_881.gif]](../Images/ComplexFunReciprocalModHome_gr_881.gif)
The
Riemann hemispheres corresponding to the unit
disk
and
the region
.
Aside. Consider the
inverse transformation ![]()
, and
the equations
and
. When
these values are substituted into
we
get
.
![]()
![]()
![[Graphics:../Images/ComplexFunReciprocalModHome_gr_893.gif]](../Images/ComplexFunReciprocalModHome_gr_893.gif)
![]()
![]()
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell