Exercise 5.  Find the image of the line  [Graphics:Images/ComplexFunReciprocalModHome_gr_179.gif]  under the reciprocal transformation  [Graphics:Images/ComplexFunReciprocalModHome_gr_180.gif].  

Make sketches and indicate the points [Graphics:Images/ComplexFunReciprocalModHome_gr_181.gif]  in the z-plane and their images [Graphics:Images/ComplexFunReciprocalModHome_gr_182.gif] in the w-plane.

Solution 5.

See text and/or instructor's solution manual.

Answer.  The circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_183.gif][Graphics:../Images/ComplexFunReciprocalModHome_gr_184.gif].  

The points [Graphics:../Images/ComplexFunReciprocalModHome_gr_185.gif]  are mapped onto  [Graphics:../Images/ComplexFunReciprocalModHome_gr_186.gif].

          

              [Graphics:../Images/ComplexFunReciprocalModHome_gr_187.gif]            [Graphics:../Images/ComplexFunReciprocalModHome_gr_188.gif]

  

Graph of the line  [Graphics:../Images/ComplexFunReciprocalModHome_gr_189.gif],  using the parametric equations  [Graphics:../Images/ComplexFunReciprocalModHome_gr_190.gif],  and the image circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_191.gif],  using the parametric equations  [Graphics:../Images/ComplexFunReciprocalModHome_gr_192.gif],   and   [Graphics:../Images/ComplexFunReciprocalModHome_gr_193.gif].  

Solution using algebra.

      The inverse mapping is  [Graphics:../Images/ComplexFunReciprocalModHome_gr_194.gif][Graphics:../Images/ComplexFunReciprocalModHome_gr_195.gif].   

Now use the substitution  [Graphics:../Images/ComplexFunReciprocalModHome_gr_196.gif]  and get:

Solution.  The inverse mapping is  [Graphics:../Images/ComplexFunReciprocalModHome_gr_197.gif][Graphics:../Images/ComplexFunReciprocalModHome_gr_198.gif].   

Now use the substitution  [Graphics:../Images/ComplexFunReciprocalModHome_gr_199.gif]  and get:

        [Graphics:../Images/ComplexFunReciprocalModHome_gr_200.gif]  

This is an equation of the circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_201.gif][Graphics:../Images/ComplexFunReciprocalModHome_gr_202.gif].  

We are done.   

          

              [Graphics:../Images/ComplexFunReciprocalModHome_gr_203.gif]            [Graphics:../Images/ComplexFunReciprocalModHome_gr_204.gif]

  

                    The line  [Graphics:../Images/ComplexFunReciprocalModHome_gr_205.gif]  and the image circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_206.gif],  divide the z-plane and w-plane into two pieces.

Solution using point images.  

      The points [Graphics:../Images/ComplexFunReciprocalModHome_gr_207.gif]  lie on the line  [Graphics:../Images/ComplexFunReciprocalModHome_gr_208.gif]  in the z-plane.  

Their image points are  [Graphics:../Images/ComplexFunReciprocalModHome_gr_209.gif],  and these three points  [Graphics:../Images/ComplexFunReciprocalModHome_gr_210.gif]  determine the circle

[Graphics:../Images/ComplexFunReciprocalModHome_gr_211.gif][Graphics:../Images/ComplexFunReciprocalModHome_gr_212.gif]   in the w-plane.  

If we observe that the center of the circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_213.gif]  is  [Graphics:../Images/ComplexFunReciprocalModHome_gr_214.gif],  then an easy calculation shows that

[Graphics:../Images/ComplexFunReciprocalModHome_gr_215.gif],  [Graphics:../Images/ComplexFunReciprocalModHome_gr_216.gif],  and  [Graphics:../Images/ComplexFunReciprocalModHome_gr_217.gif],

and we have verified this observation.  

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ComplexFunReciprocalModHome_gr_218.gif]

          

              [Graphics:../Images/ComplexFunReciprocalModHome_gr_219.gif]            [Graphics:../Images/ComplexFunReciprocalModHome_gr_220.gif]

  

                    The line  [Graphics:../Images/ComplexFunReciprocalModHome_gr_221.gif]  and the image circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_222.gif].

                    The points [Graphics:../Images/ComplexFunReciprocalModHome_gr_223.gif]  and  [Graphics:../Images/ComplexFunReciprocalModHome_gr_224.gif].

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell