Exercise 7.  Find the image of the circle   [Graphics:Images/ComplexFunReciprocalModHome_gr_274.gif]  under the reciprocal transformation  [Graphics:Images/ComplexFunReciprocalModHome_gr_275.gif].  

Make sketches and indicate the points [Graphics:Images/ComplexFunReciprocalModHome_gr_276.gif]  in the z-plane and their images [Graphics:Images/ComplexFunReciprocalModHome_gr_277.gif] in the w-plane.

Solution 7.

See text and/or instructor's solution manual.

Answer.  The circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_278.gif][Graphics:../Images/ComplexFunReciprocalModHome_gr_279.gif].  

The points  [Graphics:../Images/ComplexFunReciprocalModHome_gr_280.gif]   are mapped onto  [Graphics:../Images/ComplexFunReciprocalModHome_gr_281.gif].

          

              [Graphics:../Images/ComplexFunReciprocalModHome_gr_282.gif]            [Graphics:../Images/ComplexFunReciprocalModHome_gr_283.gif]

  

Graph of the circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_284.gif],  using the parametric equations  [Graphics:../Images/ComplexFunReciprocalModHome_gr_285.gif],  and the image circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_286.gif],  using the parametric equations  [Graphics:../Images/ComplexFunReciprocalModHome_gr_287.gif],  and  [Graphics:../Images/ComplexFunReciprocalModHome_gr_288.gif].  

Solution using algebra.

      The inverse mapping is  [Graphics:../Images/ComplexFunReciprocalModHome_gr_289.gif][Graphics:../Images/ComplexFunReciprocalModHome_gr_290.gif].   

Now use the substitution  [Graphics:../Images/ComplexFunReciprocalModHome_gr_291.gif]  and get:

        [Graphics:../Images/ComplexFunReciprocalModHome_gr_292.gif]  

This is an equation of the circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_293.gif][Graphics:../Images/ComplexFunReciprocalModHome_gr_294.gif].  

We are done.   

Remark.  The above solution depended on factoring the multivariate polynomial  [Graphics:../Images/ComplexFunReciprocalModHome_gr_295.gif].  
This is not as difficult as one might suspect because it must have [Graphics:../Images/ComplexFunReciprocalModHome_gr_296.gif] as a factor.  

          

              [Graphics:../Images/ComplexFunReciprocalModHome_gr_297.gif]            [Graphics:../Images/ComplexFunReciprocalModHome_gr_298.gif]

  

                    The circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_299.gif]  and the image circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_300.gif],  divide the z-plane and w-plane into two pieces.

Solution using point images.  

      The points [Graphics:../Images/ComplexFunReciprocalModHome_gr_301.gif]  lie on the circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_302.gif]  in the z-plane.  

Their image points are  [Graphics:../Images/ComplexFunReciprocalModHome_gr_303.gif],  and these three points  [Graphics:../Images/ComplexFunReciprocalModHome_gr_304.gif]  determine the circle  

[Graphics:../Images/ComplexFunReciprocalModHome_gr_305.gif][Graphics:../Images/ComplexFunReciprocalModHome_gr_306.gif]  in the w-plane.  

If we observe that the center of the circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_307.gif]  is  [Graphics:../Images/ComplexFunReciprocalModHome_gr_308.gif],  then an easy calculation shows that

[Graphics:../Images/ComplexFunReciprocalModHome_gr_309.gif],  [Graphics:../Images/ComplexFunReciprocalModHome_gr_310.gif],  and  [Graphics:../Images/ComplexFunReciprocalModHome_gr_311.gif],  

and we have verified this observation.  

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ComplexFunReciprocalModHome_gr_312.gif]

          

              [Graphics:../Images/ComplexFunReciprocalModHome_gr_313.gif]              [Graphics:../Images/ComplexFunReciprocalModHome_gr_314.gif]

                    The circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_315.gif]  and the image circle  [Graphics:../Images/ComplexFunReciprocalModHome_gr_316.gif].

                    The points  [Graphics:../Images/ComplexFunReciprocalModHome_gr_317.gif]   and  [Graphics:../Images/ComplexFunReciprocalModHome_gr_318.gif].

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell