Exercise 5. Show that, for all z,
5
(a).
.
Solution 5 (a).
See text and/or instructor's solution manual.
Solution. This follows immediately from the
identity
.
Aside. We can let Mathematica double check our work.
Alternate
Solution. Use the Identity
(5-34)
and
get:
We are done.
Aside. We can let Mathematica graph the compositions that are involved.
![[Graphics:../Images/ComplexFunTrigModHome_gr_113.gif]](../Images/ComplexFunTrigModHome_gr_113.gif)
![[Graphics:../Images/ComplexFunTrigModHome_gr_115.gif]](../Images/ComplexFunTrigModHome_gr_115.gif)
The
composite mappings
,
,
,
where
and
.
![[Graphics:../Images/ComplexFunTrigModHome_gr_122.gif]](../Images/ComplexFunTrigModHome_gr_122.gif)
The
equivalent mapping
.
![[Graphics:../Images/ComplexFunTrigModHome_gr_125.gif]](../Images/ComplexFunTrigModHome_gr_125.gif)
![[Graphics:../Images/ComplexFunTrigModHome_gr_127.gif]](../Images/ComplexFunTrigModHome_gr_127.gif)
The
composite mappings
,
,
,
where
and
.
![[Graphics:../Images/ComplexFunTrigModHome_gr_134.gif]](../Images/ComplexFunTrigModHome_gr_134.gif)
The
equivalent mapping
.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell