Exercise 2.  Establish the following identities.

2 (c).   [Graphics:Images/ComplexFunTrigInverseModHome_gr_397.gif].  

Solution 2 (c).

Solution.   Start with   [Graphics:../Images/ComplexFunTrigInverseModHome_gr_398.gif].    

Thus,   [Graphics:../Images/ComplexFunTrigInverseModHome_gr_399.gif].   Multiplying by  [Graphics:../Images/ComplexFunTrigInverseModHome_gr_400.gif]  and simplifying gives

                    [Graphics:../Images/ComplexFunTrigInverseModHome_gr_401.gif]  

Taking the multivalued log results in

                    [Graphics:../Images/ComplexFunTrigInverseModHome_gr_402.gif]  

Therefore,  [Graphics:../Images/ComplexFunTrigInverseModHome_gr_403.gif]

Aside.   In calculating the principal value of   [Graphics:../Images/ComplexFunTrigInverseModHome_gr_404.gif],  Mathematica manipulates this formula as follows:   

                    [Graphics:../Images/ComplexFunTrigInverseModHome_gr_405.gif]  

We are done.   

Aside.  The principal value of  [Graphics:../Images/ComplexFunTrigInverseModHome_gr_406.gif]  can be calculated with Mathematica.

[Graphics:../Images/ComplexFunTrigInverseModHome_gr_407.gif]

[Graphics:../Images/ComplexFunTrigInverseModHome_gr_408.gif]

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 



This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell