Exercise 1. Find all values of the following.
1
(i).
.
Solution 1 (i).
Answer.
where n is
an integer,
and also
where n is
an integer.
Solution. Use
the Identity in
(5-48)
and
get:
There are two choices
![]()
and
Therefore,
where n is
an integer
and also
where n is
an integer
![[Graphics:../Images/ComplexFunTrigInverseModHome_gr_264.gif]](../Images/ComplexFunTrigInverseModHome_gr_264.gif)
The
points
and
.
You may wonder why
the solutions look the way they do.
Recall that
is
an even function and the identity
holds
for all z.
We are done.
Aside. We can let Mathematica double check our work.
This can be accomplished by performing the
computations
and
.
We are really done.
Aside. The
principal value of
can
be calculated with Mathematica.
Also, we can substitute n =
0 into the general formula
and
get
We are really really done.
![[Graphics:../Images/ComplexFunTrigInverseModHome_gr_286.gif]](../Images/ComplexFunTrigInverseModHome_gr_286.gif)
The
point
and
the principal value image point
.
Remark. We will study mappings with the trigonometric functions in Section 10.4 and in some of the applications that follow in Chapter 11.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell