Exercise 3.  Is the series   [Graphics:Images/ComplexGeometricSeriesModHome_gr_63.gif]   convergent?   Why or why not?  

Solution 3.

See text and/or instructor's solution manual.

Answer.   The series converges by the ratio test.   

Solution   Write  [Graphics:../Images/ComplexGeometricSeriesModHome_gr_64.gif]  and use d'Alembert's ratio test and calculate the limit value  L:  

                    [Graphics:../Images/ComplexGeometricSeriesModHome_gr_65.gif]

Since   [Graphics:../Images/ComplexGeometricSeriesModHome_gr_66.gif],   the series   [Graphics:../Images/ComplexGeometricSeriesModHome_gr_67.gif]   will converge.  

We are done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ComplexGeometricSeriesModHome_gr_68.gif]

[Graphics:../Images/ComplexGeometricSeriesModHome_gr_69.gif]


We are really done.   

Aside.  The Taylor series for  [Graphics:../Images/ComplexGeometricSeriesModHome_gr_70.gif]  was studied in calculus, and we have  

                    [Graphics:../Images/ComplexGeometricSeriesModHome_gr_71.gif],  

which converges for all  x.

In Section 5.1 we will find that complex series are extensions of real series and we will derive the formula

                    [Graphics:../Images/ComplexGeometricSeriesModHome_gr_72.gif],

which converges for all  z.

This will give rise to the computation  

                    [Graphics:../Images/ComplexGeometricSeriesModHome_gr_73.gif]   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ComplexGeometricSeriesModHome_gr_74.gif]

[Graphics:../Images/ComplexGeometricSeriesModHome_gr_75.gif]



[Graphics:../Images/ComplexGeometricSeriesModHome_gr_76.gif]

[Graphics:../Images/ComplexGeometricSeriesModHome_gr_77.gif]

                    [Graphics:../Images/ComplexGeometricSeriesModHome_gr_78.gif]

                    A few of the partial sums  [Graphics:../Images/ComplexGeometricSeriesModHome_gr_79.gif],  and the limit point  [Graphics:../Images/ComplexGeometricSeriesModHome_gr_80.gif].

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell