Exercise 7. Prove
that
.
Solution 7.
See text and/or instructor's solution manual.
Let
.
Then ![]()
iff ![]()
iff ![]()
iff ![]()
iff ![]()
iff ![]()
iff ![]()
iff
, which
is clearly true.
A proper argument will start with this last inequality and work
backwards to the appropriate conclusion.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell