Exercise 15.  Show that  [Graphics:Images/ComplexGeometryModHome_gr_214.gif].

Solution 15.

See text and/or instructor's solution manual.

By repeated application of equation (1-25), we have  

        [Graphics:../Images/ComplexGeometryModHome_gr_215.gif]  
        
        [Graphics:../Images/ComplexGeometryModHome_gr_216.gif][Graphics:../Images/ComplexGeometryModHome_gr_217.gif]  
        
        [Graphics:../Images/ComplexGeometryModHome_gr_218.gif][Graphics:../Images/ComplexGeometryModHome_gr_219.gif][Graphics:../Images/ComplexGeometryModHome_gr_220.gif]    



































 

This solution is complements of the authors.





















































 

(c) 2008 John H. Mathews, Russell W. Howell