Exercise
3. Represent the following complex numbers in
polar form
.
3 (c).
.
Solution 3 (c).
See text and/or instructor's solution manual.
The modulus of
is
and an argument is
.
Hence, the polar form of
is
, i.e.
![]()
We are done.
Aside. We can let Mathematica double check our work.
![[Graphics:../Images/ComplexGeometryContinuedModHome_gr_192.gif]](../Images/ComplexGeometryContinuedModHome_gr_192.gif)
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell