Exercise 9.  Describe the set of complex numbers for which  [Graphics:Images/ComplexGeometryContinuedModHome_gr_340.gif].  Prove your assertion.  

Solution 9.

See text and/or instructor's solution manual.

    Answer:  The negative real numbers and the number   [Graphics:../Images/ComplexGeometryContinuedModHome_gr_341.gif]  .  Prove this!

    Assume that z is a complex number that is not a negative real number or zero.   Then [Graphics:../Images/ComplexGeometryContinuedModHome_gr_342.gif] and [Graphics:../Images/ComplexGeometryContinuedModHome_gr_343.gif], and z can be represented in polar coordinates as

        [Graphics:../Images/ComplexGeometryContinuedModHome_gr_344.gif]  where  [Graphics:../Images/ComplexGeometryContinuedModHome_gr_345.gif].  Then  [Graphics:../Images/ComplexGeometryContinuedModHome_gr_346.gif]  and  [Graphics:../Images/ComplexGeometryContinuedModHome_gr_347.gif].  

This proves that  [Graphics:../Images/ComplexGeometryContinuedModHome_gr_348.gif]  when z is not a negative real number or zero.

    If   [Graphics:../Images/ComplexGeometryContinuedModHome_gr_349.gif]  .  then [Graphics:../Images/ComplexGeometryContinuedModHome_gr_350.gif],  [Graphics:../Images/ComplexGeometryContinuedModHome_gr_351.gif] , and [Graphics:../Images/ComplexGeometryContinuedModHome_gr_352.gif] are all undefined.  So  [Graphics:../Images/ComplexGeometryContinuedModHome_gr_353.gif] by default.

If  z  is a negative real number then  [Graphics:../Images/ComplexGeometryContinuedModHome_gr_354.gif],  where [Graphics:../Images/ComplexGeometryContinuedModHome_gr_355.gif].  Calculation reveals that  [Graphics:../Images/ComplexGeometryContinuedModHome_gr_356.gif],  and  [Graphics:../Images/ComplexGeometryContinuedModHome_gr_357.gif].  In this case we see that  

        [Graphics:../Images/ComplexGeometryContinuedModHome_gr_358.gif],  
and
        [Graphics:../Images/ComplexGeometryContinuedModHome_gr_359.gif].

Therefore,  [Graphics:../Images/ComplexGeometryContinuedModHome_gr_360.gif]  when  z  is a negative real number.



















 

This solution is complements of the authors.







































 

(c) 2008 John H. Mathews, Russell W. Howell