Exercise 1.  Find  [Graphics:Images/ComplexGeometryContinuedModHome_gr_1.gif]  for the following values of  z.  

1 (d).  [Graphics:Images/ComplexGeometryContinuedModHome_gr_43.gif].  

Solution 1 (d).

See text and/or instructor's solution manual.

One solution is obtained by multiplying out the quantity  [Graphics:../Images/ComplexGeometryContinuedModHome_gr_44.gif] as follows:

        [Graphics:../Images/ComplexGeometryContinuedModHome_gr_45.gif]

then

        [Graphics:../Images/ComplexGeometryContinuedModHome_gr_46.gif]  

Warning.  We obtain the calculated value  [Graphics:../Images/ComplexGeometryContinuedModHome_gr_47.gif]  which is not the argument for a complex number in Quadrant III.    

To obtain the correct value of the argument we must subtract  [Graphics:../Images/ComplexGeometryContinuedModHome_gr_48.gif],  i.e.  [Graphics:../Images/ComplexGeometryContinuedModHome_gr_49.gif].

For this example we need to use the formula for ArcTan that has two arguments (no pun intended) : [Graphics:../Images/ComplexGeometryContinuedModHome_gr_50.gif].

We are done.   

    Another solution is obtained by using the formula  [Graphics:../Images/ComplexGeometryContinuedModHome_gr_51.gif],  where n is an integer.

In our case, this becomes    [Graphics:../Images/ComplexGeometryContinuedModHome_gr_52.gif],  where n is an integer.

        [Graphics:../Images/ComplexGeometryContinuedModHome_gr_53.gif].  

If we choose  [Graphics:../Images/ComplexGeometryContinuedModHome_gr_54.gif],  then  [Graphics:../Images/ComplexGeometryContinuedModHome_gr_55.gif]  lies in the interval[Graphics:../Images/ComplexGeometryContinuedModHome_gr_56.gif],  

so the principal value of the argument is found to be

        [Graphics:../Images/ComplexGeometryContinuedModHome_gr_57.gif]

We are done.   

Aside.  We can let Mathematica double check our work.

        

[Graphics:../Images/ComplexGeometryContinuedModHome_gr_58.gif]

  

[Graphics:../Images/ComplexGeometryContinuedModHome_gr_59.gif]
[Graphics:../Images/ComplexGeometryContinuedModHome_gr_60.gif]
[Graphics:../Images/ComplexGeometryContinuedModHome_gr_61.gif]




















This solution is complements of the authors.







































 

(c) 2008 John H. Mathews, Russell W. Howell