Exercise 5.  Use Bombelli's technique to get all solutions to the following depressed cubics.  
5 (a).  [Graphics:Images/ComplexNumberOriginHome_gr_74.gif].  

Solution 5 (a).

See text and/or instructor's solution manual.

To solve  [Graphics:../Images/ComplexNumberOriginHome_gr_77.gif].  

Use the formula  [Graphics:../Images/ComplexNumberOriginHome_gr_78.gif]  for solving the depressed cubic  [Graphics:../Images/ComplexNumberOriginHome_gr_79.gif].  
Substitute  [Graphics:../Images/ComplexNumberOriginHome_gr_80.gif],  [Graphics:../Images/ComplexNumberOriginHome_gr_81.gif],  and get  [Graphics:../Images/ComplexNumberOriginHome_gr_82.gif],  
which simplifies to be  [Graphics:../Images/ComplexNumberOriginHome_gr_83.gif].  

Assume, as Bombelli did that this expression can be put in the form  [Graphics:../Images/ComplexNumberOriginHome_gr_84.gif],  where u and v are integers.  
      
Next, imitate the argument in the text that leads to equations (1-4), (1-5) and (1-6) to get  [Graphics:../Images/ComplexNumberOriginHome_gr_85.gif].  

The only factors of 18 are [Graphics:../Images/ComplexNumberOriginHome_gr_86.gif], so you can deduce (explain your reasoning) that  [Graphics:../Images/ComplexNumberOriginHome_gr_87.gif]  and  [Graphics:../Images/ComplexNumberOriginHome_gr_88.gif]  solve this system.  

Thus, one solution to  [Graphics:../Images/ComplexNumberOriginHome_gr_89.gif]  is  [Graphics:../Images/ComplexNumberOriginHome_gr_90.gif].

Divide  [Graphics:../Images/ComplexNumberOriginHome_gr_91.gif]  by  [Graphics:../Images/ComplexNumberOriginHome_gr_92.gif]  and get  [Graphics:../Images/ComplexNumberOriginHome_gr_93.gif],  
and then solve the resulting quadratic to get the remaining solutions:  [Graphics:../Images/ComplexNumberOriginHome_gr_94.gif] and  [Graphics:../Images/ComplexNumberOriginHome_gr_95.gif].  

We are done.  The roots are   [Graphics:../Images/ComplexNumberOriginHome_gr_96.gif].

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ComplexNumberOriginHome_gr_97.gif]
[Graphics:../Images/ComplexNumberOriginHome_gr_98.gif]

An equivalent polynomial is  [Graphics:../Images/ComplexNumberOriginHome_gr_99.gif].

[Graphics:../Images/ComplexNumberOriginHome_gr_100.gif]
[Graphics:../Images/ComplexNumberOriginHome_gr_101.gif]
[Graphics:../Images/ComplexNumberOriginHome_gr_102.gif]

[Graphics:../Images/ComplexNumberOriginHome_gr_103.gif]

Caveat.  You might wonder.
Why use the technique of good guessing to find that  [Graphics:../Images/ComplexNumberOriginHome_gr_104.gif]  and  [Graphics:../Images/ComplexNumberOriginHome_gr_105.gif]  solve this system  [Graphics:../Images/ComplexNumberOriginHome_gr_106.gif] ?
Why not let computer software solve the equation  [Graphics:../Images/ComplexNumberOriginHome_gr_107.gif]  for u and v ?

[Graphics:../Images/ComplexNumberOriginHome_gr_108.gif]
[Graphics:../Images/ComplexNumberOriginHome_gr_109.gif]

Clearly there is only one solution in integers.

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell