Exercise 5.  Use Bombelli's technique to get all solutions to the following depressed cubics.  
5 (c).  [Graphics:Images/ComplexNumberOriginHome_gr_76.gif].  

Solution 5 (c).

See text and/or instructor's solution manual.

To solve  [Graphics:../Images/ComplexNumberOriginHome_gr_143.gif].  

Use the formula  [Graphics:../Images/ComplexNumberOriginHome_gr_144.gif]  for solving the depressed cubic  [Graphics:../Images/ComplexNumberOriginHome_gr_145.gif].  
Substitute  [Graphics:../Images/ComplexNumberOriginHome_gr_146.gif],  [Graphics:../Images/ComplexNumberOriginHome_gr_147.gif],  and get  [Graphics:../Images/ComplexNumberOriginHome_gr_148.gif],  
which simplifies to be  [Graphics:../Images/ComplexNumberOriginHome_gr_149.gif].  

Assume, as Bombelli did that this expression can be put in the form  [Graphics:../Images/ComplexNumberOriginHome_gr_150.gif],  where u and v are integers.  
      
Next, imitate the argument in the text that leads to equations (1-4), (1-5) and (1-6) to get  [Graphics:../Images/ComplexNumberOriginHome_gr_151.gif].  

The only factors of 16 are [Graphics:../Images/ComplexNumberOriginHome_gr_152.gif], so you can deduce (explain your reasoning) that  [Graphics:../Images/ComplexNumberOriginHome_gr_153.gif]  and  [Graphics:../Images/ComplexNumberOriginHome_gr_154.gif]  solve this system.  

Thus, one solution to  [Graphics:../Images/ComplexNumberOriginHome_gr_155.gif]  is  [Graphics:../Images/ComplexNumberOriginHome_gr_156.gif].

Divide  [Graphics:../Images/ComplexNumberOriginHome_gr_157.gif]  by  [Graphics:../Images/ComplexNumberOriginHome_gr_158.gif]  and get  [Graphics:../Images/ComplexNumberOriginHome_gr_159.gif],  
and then solve the resulting quadratic to get the remaining solutions:  [Graphics:../Images/ComplexNumberOriginHome_gr_160.gif] and  [Graphics:../Images/ComplexNumberOriginHome_gr_161.gif].  

We are done.  The roots are   [Graphics:../Images/ComplexNumberOriginHome_gr_162.gif].

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ComplexNumberOriginHome_gr_163.gif]
[Graphics:../Images/ComplexNumberOriginHome_gr_164.gif]

An equivalent polynomial is  [Graphics:../Images/ComplexNumberOriginHome_gr_165.gif].

[Graphics:../Images/ComplexNumberOriginHome_gr_166.gif]
[Graphics:../Images/ComplexNumberOriginHome_gr_167.gif]
[Graphics:../Images/ComplexNumberOriginHome_gr_168.gif]

[Graphics:../Images/ComplexNumberOriginHome_gr_169.gif]

Caveat.  You might wonder.
Why use the technique of good guessing to find that  [Graphics:../Images/ComplexNumberOriginHome_gr_170.gif]  and  [Graphics:../Images/ComplexNumberOriginHome_gr_171.gif]  solve this system  [Graphics:../Images/ComplexNumberOriginHome_gr_172.gif] ?
Why not let computer software solve the equation  [Graphics:../Images/ComplexNumberOriginHome_gr_173.gif]  for u and v ?

[Graphics:../Images/ComplexNumberOriginHome_gr_174.gif]
[Graphics:../Images/ComplexNumberOriginHome_gr_175.gif]

Clearly there is only one solution in integers.

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell