Example 4.24.  Show that   [Graphics:Images/ComplexPowerSeriesMod_gr_190.gif]   for all  [Graphics:Images/ComplexPowerSeriesMod_gr_191.gif]

Solution.  We know from Theorem 4.12 that  [Graphics:Images/ComplexPowerSeriesMod_gr_192.gif]  for all  [Graphics:Images/ComplexPowerSeriesMod_gr_193.gif].  If we set k=1 in Theorem 4.16, part (ii), then

              [Graphics:Images/ComplexPowerSeriesMod_gr_194.gif],

for all  [Graphics:Images/ComplexPowerSeriesMod_gr_195.gif].

Explore Solution 4.24.

Use the fact that  [Graphics:../Images/ComplexPowerSeriesMod_gr_196.gif]  and  [Graphics:../Images/ComplexPowerSeriesMod_gr_197.gif].  

[Graphics:../Images/ComplexPowerSeriesMod_gr_198.gif]




[Graphics:../Images/ComplexPowerSeriesMod_gr_199.gif]

 

 

 

Or sum the infinite series directly.

[Graphics:../Images/ComplexPowerSeriesMod_gr_200.gif]




[Graphics:../Images/ComplexPowerSeriesMod_gr_201.gif]

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2006 John H. Mathews, Russell W. Howell