Exercise 1.  Prove part (iii) d'Alembert's Ratio Test of Theorem 4.16 .  

Solution 1.

See text and/or instructor's solution manual.

Solution.  Given  [Graphics:../Images/ComplexPowerSeriesModHome_gr_1.gif] .  

We must prove that if  [Graphics:../Images/ComplexPowerSeriesModHome_gr_2.gif] and then the series converges for all  [Graphics:../Images/ComplexPowerSeriesModHome_gr_3.gif].

Recall Theorem 4.13 which we asked you to prove in Exercise 9 in Section 4.3.  If  [Graphics:../Images/ComplexPowerSeriesModHome_gr_4.gif]  is a complex series with the property that  

            [Graphics:../Images/ComplexPowerSeriesModHome_gr_5.gif],  

then the series converges absolutely if  [Graphics:../Images/ComplexPowerSeriesModHome_gr_6.gif]  and diverges if  [Graphics:../Images/ComplexPowerSeriesModHome_gr_7.gif].  

Set [Graphics:../Images/ComplexPowerSeriesModHome_gr_8.gif] and apply  Theorem 4.13.  

The series  [Graphics:../Images/ComplexPowerSeriesModHome_gr_9.gif]  converges absolutely if   [Graphics:../Images/ComplexPowerSeriesModHome_gr_10.gif][Graphics:../Images/ComplexPowerSeriesModHome_gr_11.gif],  and

the series  [Graphics:../Images/ComplexPowerSeriesModHome_gr_12.gif]  diverges if   [Graphics:../Images/ComplexPowerSeriesModHome_gr_13.gif][Graphics:../Images/ComplexPowerSeriesModHome_gr_14.gif].  

Thus, the series  [Graphics:../Images/ComplexPowerSeriesModHome_gr_15.gif]  converges absolutely if   [Graphics:../Images/ComplexPowerSeriesModHome_gr_16.gif][Graphics:../Images/ComplexPowerSeriesModHome_gr_17.gif].

If   [Graphics:../Images/ComplexPowerSeriesModHome_gr_18.gif]   is finite but not zero, then the series  [Graphics:../Images/ComplexPowerSeriesModHome_gr_19.gif]  converges if  [Graphics:../Images/ComplexPowerSeriesModHome_gr_20.gif].  

If   [Graphics:../Images/ComplexPowerSeriesModHome_gr_21.gif],   the series  [Graphics:../Images/ComplexPowerSeriesModHome_gr_22.gif]  converges for all  z.

If   [Graphics:../Images/ComplexPowerSeriesModHome_gr_23.gif],   the series converges only at the single point  [Graphics:../Images/ComplexPowerSeriesModHome_gr_24.gif].  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell