Exercise 3.  Find the radius of convergence of the following.  

3 (c).  [Graphics:Images/ComplexPowerSeriesModHome_gr_218.gif].  

Solution 3 (c).

See text and/or instructor's solution manual.

Answer   The radius of convergence of  [Graphics:../Images/ComplexPowerSeriesModHome_gr_219.gif]  is   [Graphics:../Images/ComplexPowerSeriesModHome_gr_220.gif].

Solution.  For   [Graphics:../Images/ComplexPowerSeriesModHome_gr_221.gif],  we have  [Graphics:../Images/ComplexPowerSeriesModHome_gr_222.gif].  

Use Theorem 4.16 and calculate the limit in Cauchy's Root Test:   

                    [Graphics:../Images/ComplexPowerSeriesModHome_gr_223.gif]  
                    
The radius of convergence of the series  [Graphics:../Images/ComplexPowerSeriesModHome_gr_224.gif]  is  [Graphics:../Images/ComplexPowerSeriesModHome_gr_225.gif].

Thus   [Graphics:../Images/ComplexPowerSeriesModHome_gr_226.gif]   converges for all  [Graphics:../Images/ComplexPowerSeriesModHome_gr_227.gif].

We are done.   

Aside.  We can let Mathematica double check our work.

                                                                                [Graphics:../Images/ComplexPowerSeriesModHome_gr_228.gif]

                              The domain set  [Graphics:../Images/ComplexPowerSeriesModHome_gr_229.gif]  that is used to produce the images under  [Graphics:../Images/ComplexPowerSeriesModHome_gr_230.gif]

 

[Graphics:../Images/ComplexPowerSeriesModHome_gr_231.gif]          [Graphics:../Images/ComplexPowerSeriesModHome_gr_232.gif]          [Graphics:../Images/ComplexPowerSeriesModHome_gr_233.gif]


[Graphics:../Images/ComplexPowerSeriesModHome_gr_234.gif]          [Graphics:../Images/ComplexPowerSeriesModHome_gr_235.gif]          [Graphics:../Images/ComplexPowerSeriesModHome_gr_236.gif]

     Graphs of the mappings  [Graphics:../Images/ComplexPowerSeriesModHome_gr_237.gif],   [Graphics:../Images/ComplexPowerSeriesModHome_gr_238.gif],   [Graphics:../Images/ComplexPowerSeriesModHome_gr_239.gif],   [Graphics:../Images/ComplexPowerSeriesModHome_gr_240.gif],   [Graphics:../Images/ComplexPowerSeriesModHome_gr_241.gif],   and   [Graphics:../Images/ComplexPowerSeriesModHome_gr_242.gif].

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell