Exercise 3.  Find the radius of convergence of the following.  

3 (e).  [Graphics:Images/ComplexPowerSeriesModHome_gr_287.gif].  

Solution 3 (e).

See text and/or instructor's solution manual.

Answer   The radius of convergence of  [Graphics:../Images/ComplexPowerSeriesModHome_gr_288.gif]  is   [Graphics:../Images/ComplexPowerSeriesModHome_gr_289.gif].

Solution.  For   [Graphics:../Images/ComplexPowerSeriesModHome_gr_290.gif],  we have  [Graphics:../Images/ComplexPowerSeriesModHome_gr_291.gif].  

Use Theorem 4.16 and calculate the limit superior in the Cauchy-Hadamard Formula:    

                    [Graphics:../Images/ComplexPowerSeriesModHome_gr_292.gif].

The radius of convergence of the series  [Graphics:../Images/ComplexPowerSeriesModHome_gr_293.gif]  is  [Graphics:../Images/ComplexPowerSeriesModHome_gr_294.gif].

Thus   [Graphics:../Images/ComplexPowerSeriesModHome_gr_295.gif]  converges for all  [Graphics:../Images/ComplexPowerSeriesModHome_gr_296.gif].

We are done.   

Aside.  We can split this series up into two familiar geometric series:  

                    [Graphics:../Images/ComplexPowerSeriesModHome_gr_297.gif].

The first series is

                    [Graphics:../Images/ComplexPowerSeriesModHome_gr_298.gif],   and it converges for  [Graphics:../Images/ComplexPowerSeriesModHome_gr_299.gif].

The second series is

                    [Graphics:../Images/ComplexPowerSeriesModHome_gr_300.gif],  and it converges for  [Graphics:../Images/ComplexPowerSeriesModHome_gr_301.gif].

Therefore, the series is

                    [Graphics:../Images/ComplexPowerSeriesModHome_gr_302.gif],  

converges for  [Graphics:../Images/ComplexPowerSeriesModHome_gr_303.gif].   

Therefore, the radius of convergence of the series  [Graphics:../Images/ComplexPowerSeriesModHome_gr_304.gif]  is  [Graphics:../Images/ComplexPowerSeriesModHome_gr_305.gif].

Thus   [Graphics:../Images/ComplexPowerSeriesModHome_gr_306.gif]  converges for all  [Graphics:../Images/ComplexPowerSeriesModHome_gr_307.gif].

We are really done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ComplexPowerSeriesModHome_gr_308.gif]

[Graphics:../Images/ComplexPowerSeriesModHome_gr_309.gif]

                                                                                [Graphics:../Images/ComplexPowerSeriesModHome_gr_310.gif]

                              The domain set  [Graphics:../Images/ComplexPowerSeriesModHome_gr_311.gif]  that is used to produce the images under  [Graphics:../Images/ComplexPowerSeriesModHome_gr_312.gif]

 

[Graphics:../Images/ComplexPowerSeriesModHome_gr_313.gif]          [Graphics:../Images/ComplexPowerSeriesModHome_gr_314.gif]          [Graphics:../Images/ComplexPowerSeriesModHome_gr_315.gif]


[Graphics:../Images/ComplexPowerSeriesModHome_gr_316.gif]          [Graphics:../Images/ComplexPowerSeriesModHome_gr_317.gif]          [Graphics:../Images/ComplexPowerSeriesModHome_gr_318.gif]

     Graphs of the mappings  [Graphics:../Images/ComplexPowerSeriesModHome_gr_319.gif],   [Graphics:../Images/ComplexPowerSeriesModHome_gr_320.gif],   [Graphics:../Images/ComplexPowerSeriesModHome_gr_321.gif],   [Graphics:../Images/ComplexPowerSeriesModHome_gr_322.gif],   [Graphics:../Images/ComplexPowerSeriesModHome_gr_323.gif],   and   [Graphics:../Images/ComplexPowerSeriesModHome_gr_324.gif].

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell