Exercise 9.  Show that, if      converges, then   .   

Hint.  ,   where    .

Solution 9.

See text and/or instructor's solution manual.

Solution.  Since    converges, we have  ,  where S is a complex number.   

But then   ,   so that

                       

This solution is complements of the authors.

(c) 2008 John H. Mathews, Russell W. Howell