Solution 17.

See text and/or instructor's solution manual.

Solution.   Let   [Graphics:../Images/ComplexSequenceSeriesModHome_gr_371.gif]   and suppose   [Graphics:../Images/ComplexSequenceSeriesModHome_gr_372.gif].   

This means there exists and  [Graphics:../Images/ComplexSequenceSeriesModHome_gr_373.gif]  such that  [Graphics:../Images/ComplexSequenceSeriesModHome_gr_374.gif]  implies that  [Graphics:../Images/ComplexSequenceSeriesModHome_gr_375.gif],  that is,  [Graphics:../Images/ComplexSequenceSeriesModHome_gr_376.gif].  

But then   [Graphics:../Images/ComplexSequenceSeriesModHome_gr_377.gif],   so also we have   [Graphics:../Images/ComplexSequenceSeriesModHome_gr_378.gif],   for all   [Graphics:../Images/ComplexSequenceSeriesModHome_gr_379.gif].  

Therefore,   [Graphics:../Images/ComplexSequenceSeriesModHome_gr_380.gif].   

      The other direction is similar.   Let   [Graphics:../Images/ComplexSequenceSeriesModHome_gr_381.gif]   and suppose   [Graphics:../Images/ComplexSequenceSeriesModHome_gr_382.gif].   

This means there exists and  [Graphics:../Images/ComplexSequenceSeriesModHome_gr_383.gif]  such that  [Graphics:../Images/ComplexSequenceSeriesModHome_gr_384.gif]  implies that   [Graphics:../Images/ComplexSequenceSeriesModHome_gr_385.gif].

But then  [Graphics:../Images/ComplexSequenceSeriesModHome_gr_386.gif],   so also we have   [Graphics:../Images/ComplexSequenceSeriesModHome_gr_387.gif],   for all   [Graphics:../Images/ComplexSequenceSeriesModHome_gr_388.gif].      

Therefore,    [Graphics:../Images/ComplexSequenceSeriesModHome_gr_389.gif].   

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell