Exercise 1.  State where the following mappings are conformal.  

1. (b)   [Graphics:Images/ConformalMappingModHome_gr_21.gif].  

Solution 1 (b).

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/ConformalMappingModHome_gr_22.gif]  is conformal for all [Graphics:../Images/ConformalMappingModHome_gr_23.gif] except  [Graphics:../Images/ConformalMappingModHome_gr_24.gif]  where  [Graphics:../Images/ConformalMappingModHome_gr_25.gif]  is an integer.  

Solution.   Calculate [Graphics:../Images/ConformalMappingModHome_gr_26.gif] and determine where  [Graphics:../Images/ConformalMappingModHome_gr_27.gif].  

                    [Graphics:../Images/ConformalMappingModHome_gr_28.gif]   

It is known that  [Graphics:../Images/ConformalMappingModHome_gr_29.gif],  where [Graphics:../Images/ConformalMappingModHome_gr_30.gif] is an integer.  

Therefore, [Graphics:../Images/ConformalMappingModHome_gr_31.gif]  is conformal for all [Graphics:../Images/ConformalMappingModHome_gr_32.gif] except  [Graphics:../Images/ConformalMappingModHome_gr_33.gif]  where  [Graphics:../Images/ConformalMappingModHome_gr_34.gif]  is an integer.  

We are done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ConformalMappingModHome_gr_35.gif]

[Graphics:../Images/ConformalMappingModHome_gr_36.gif]


[Graphics:../Images/ConformalMappingModHome_gr_37.gif]

[Graphics:../Images/ConformalMappingModHome_gr_38.gif]
[Graphics:../Images/ConformalMappingModHome_gr_39.gif]


[Graphics:../Images/ConformalMappingModHome_gr_40.gif]

[Graphics:../Images/ConformalMappingModHome_gr_41.gif]

We are really done.   

Aside.  We can let Mathematica illustrate our work.

                    [Graphics:../Images/ConformalMappingModHome_gr_42.gif]          [Graphics:../Images/ConformalMappingModHome_gr_43.gif]

                    A small portion of the mapping  [Graphics:../Images/ConformalMappingModHome_gr_44.gif].  

                    [Graphics:../Images/ConformalMappingModHome_gr_45.gif]          [Graphics:../Images/ConformalMappingModHome_gr_46.gif]

                    Another small portion of the mapping  [Graphics:../Images/ConformalMappingModHome_gr_47.gif].  

 

 

We are really really done.

Caveat.  At a point  [Graphics:../Images/ConformalMappingModHome_gr_48.gif]  where  [Graphics:../Images/ConformalMappingModHome_gr_49.gif]   we will have

                    [Graphics:../Images/ConformalMappingModHome_gr_50.gif].

Applying Theorem 10.2 we see that the mapping  [Graphics:../Images/ConformalMappingModHome_gr_51.gif] magnifies angles at the vertex [Graphics:../Images/ConformalMappingModHome_gr_52.gif] by the factor  [Graphics:../Images/ConformalMappingModHome_gr_53.gif].

                    [Graphics:../Images/ConformalMappingModHome_gr_54.gif]          [Graphics:../Images/ConformalMappingModHome_gr_55.gif]

                      For   [Graphics:../Images/ConformalMappingModHome_gr_56.gif]  at  [Graphics:../Images/ConformalMappingModHome_gr_57.gif]  we have   [Graphics:../Images/ConformalMappingModHome_gr_58.gif]   and   [Graphics:../Images/ConformalMappingModHome_gr_59.gif],  and
                      the mapping  [Graphics:../Images/ConformalMappingModHome_gr_60.gif] magnifies angles at the vertex  [Graphics:../Images/ConformalMappingModHome_gr_61.gif]  by the factor  [Graphics:../Images/ConformalMappingModHome_gr_62.gif].

 

Remark.  In Section 10.4 we will study some trigonometric mappings, including  [Graphics:../Images/ConformalMappingModHome_gr_63.gif].

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell