Exercise 1.  State where the following mappings are conformal.  

1. (c)   [Graphics:Images/ConformalMappingModHome_gr_64.gif].  

Solution 1 (c).

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/ConformalMappingModHome_gr_65.gif]  is conformal for all [Graphics:../Images/ConformalMappingModHome_gr_66.gif] except  [Graphics:../Images/ConformalMappingModHome_gr_67.gif].  

Solution.   Calculate [Graphics:../Images/ConformalMappingModHome_gr_68.gif] and determine where  [Graphics:../Images/ConformalMappingModHome_gr_69.gif].  

                    [Graphics:../Images/ConformalMappingModHome_gr_70.gif]   

It is easy to see that  [Graphics:../Images/ConformalMappingModHome_gr_71.gif]  only at the point  [Graphics:../Images/ConformalMappingModHome_gr_72.gif].  

Therefore, [Graphics:../Images/ConformalMappingModHome_gr_73.gif]  is conformal for all [Graphics:../Images/ConformalMappingModHome_gr_74.gif] except  [Graphics:../Images/ConformalMappingModHome_gr_75.gif].  

We are done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ConformalMappingModHome_gr_76.gif]

[Graphics:../Images/ConformalMappingModHome_gr_77.gif]


[Graphics:../Images/ConformalMappingModHome_gr_78.gif]

[Graphics:../Images/ConformalMappingModHome_gr_79.gif]

We are really done.   

Aside.  We can let Mathematica illustrate our work.

                    [Graphics:../Images/ConformalMappingModHome_gr_80.gif]          [Graphics:../Images/ConformalMappingModHome_gr_81.gif]

                    A small portion of the mapping  [Graphics:../Images/ConformalMappingModHome_gr_82.gif].  

                    [Graphics:../Images/ConformalMappingModHome_gr_83.gif]          [Graphics:../Images/ConformalMappingModHome_gr_84.gif]

                    Another small portion of the mapping  [Graphics:../Images/ConformalMappingModHome_gr_85.gif].  

 

 

We are really really done.

Caveat.  At a point  [Graphics:../Images/ConformalMappingModHome_gr_86.gif]  where  [Graphics:../Images/ConformalMappingModHome_gr_87.gif]   we will have

                    [Graphics:../Images/ConformalMappingModHome_gr_88.gif].

Applying Theorem 10.2 we see that the mapping  [Graphics:../Images/ConformalMappingModHome_gr_89.gif] magnifies angles at the vertex  [Graphics:../Images/ConformalMappingModHome_gr_90.gif]  by the factor  [Graphics:../Images/ConformalMappingModHome_gr_91.gif].

                    [Graphics:../Images/ConformalMappingModHome_gr_92.gif]          [Graphics:../Images/ConformalMappingModHome_gr_93.gif]

                      For   [Graphics:../Images/ConformalMappingModHome_gr_94.gif]  at  [Graphics:../Images/ConformalMappingModHome_gr_95.gif]  we have   [Graphics:../Images/ConformalMappingModHome_gr_96.gif]   and   [Graphics:../Images/ConformalMappingModHome_gr_97.gif],  and
                      the mapping  [Graphics:../Images/ConformalMappingModHome_gr_98.gif] magnifies angles at the vertex  [Graphics:../Images/ConformalMappingModHome_gr_99.gif]  by the factor  [Graphics:../Images/ConformalMappingModHome_gr_100.gif].

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell