Exercise 1.  State where the following mappings are conformal.  

1. (e)   [Graphics:Images/ConformalMappingModHome_gr_143.gif].  

Solution 1 (e).

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/ConformalMappingModHome_gr_144.gif]  is conformal for all [Graphics:../Images/ConformalMappingModHome_gr_145.gif] except  [Graphics:../Images/ConformalMappingModHome_gr_146.gif].  

Solution.   Calculate [Graphics:../Images/ConformalMappingModHome_gr_147.gif] and determine where  [Graphics:../Images/ConformalMappingModHome_gr_148.gif].  

                    [Graphics:../Images/ConformalMappingModHome_gr_149.gif]   

It is easy to see that  [Graphics:../Images/ConformalMappingModHome_gr_150.gif].  

However,  [Graphics:../Images/ConformalMappingModHome_gr_151.gif]  is not defined at the point  [Graphics:../Images/ConformalMappingModHome_gr_152.gif].  

Therefore, [Graphics:../Images/ConformalMappingModHome_gr_153.gif]  is conformal for all [Graphics:../Images/ConformalMappingModHome_gr_154.gif] except  [Graphics:../Images/ConformalMappingModHome_gr_155.gif].  

We are done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ConformalMappingModHome_gr_156.gif]

[Graphics:../Images/ConformalMappingModHome_gr_157.gif]


[Graphics:../Images/ConformalMappingModHome_gr_158.gif]

[Graphics:../Images/ConformalMappingModHome_gr_159.gif]


[Graphics:../Images/ConformalMappingModHome_gr_160.gif]

[Graphics:../Images/ConformalMappingModHome_gr_161.gif]

We are really done.   

Aside.  We can let Mathematica illustrate our work.

                    [Graphics:../Images/ConformalMappingModHome_gr_162.gif]          [Graphics:../Images/ConformalMappingModHome_gr_163.gif]

                                        A small portion of the mapping  [Graphics:../Images/ConformalMappingModHome_gr_164.gif].  

                    [Graphics:../Images/ConformalMappingModHome_gr_165.gif]          [Graphics:../Images/ConformalMappingModHome_gr_166.gif]

                    Another small portion of the mapping  [Graphics:../Images/ConformalMappingModHome_gr_167.gif].  

                    [Graphics:../Images/ConformalMappingModHome_gr_168.gif]          [Graphics:../Images/ConformalMappingModHome_gr_169.gif]

                    Yet another small portion of the mapping  [Graphics:../Images/ConformalMappingModHome_gr_170.gif].  

 

Remarks.  In Section 2.5 we saw that the reciprocal transformation  [Graphics:../Images/ConformalMappingModHome_gr_171.gif]  maps "generalized circles" onto "generalized circles."

In Section 10.2 we will see that the transformation  [Graphics:../Images/ConformalMappingModHome_gr_172.gif]  will also map "generalized circles" onto "generalized circles."

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell