Example  6.9.  Show that  [Graphics:Images/ContourIntegralMod_gr_203.gif],   
where  [Graphics:Images/ContourIntegralMod_gr_204.gif] is the line segment from  [Graphics:Images/ContourIntegralMod_gr_205.gif],  and [Graphics:Images/ContourIntegralMod_gr_206.gif] is the portion of the parabola  [Graphics:Images/ContourIntegralMod_gr_207.gif]  joining  [Graphics:Images/ContourIntegralMod_gr_208.gif],  as indicated in Figure 6.8.  

Figure 6.8  The two contours [Graphics:Images/ContourIntegralMod_gr_211.gif] and [Graphics:Images/ContourIntegralMod_gr_212.gif] joining  [Graphics:Images/ContourIntegralMod_gr_213.gif].

Explore Solution 6.9 (a)


(a)
  Use the straight line segment connecting the points  [Graphics:../Images/ContourIntegralMod_gr_238.gif],  set up the parameterization and compute the contour integral.  Enter the function  [Graphics:../Images/ContourIntegralMod_gr_239.gif].  

[Graphics:../Images/ContourIntegralMod_gr_240.gif]




[Graphics:../Images/ContourIntegralMod_gr_241.gif]

 

 

Method (i).  The integral can be computed using the real and imaginary parts.

[Graphics:../Images/ContourIntegralMod_gr_242.gif]




[Graphics:../Images/ContourIntegralMod_gr_243.gif]

[Graphics:../Images/ContourIntegralMod_gr_244.gif]

[Graphics:../Images/ContourIntegralMod_gr_245.gif]

 

 

 

Method (ii).  The integral can be computed using a complex integrand.

[Graphics:../Images/ContourIntegralMod_gr_246.gif]




[Graphics:../Images/ContourIntegralMod_gr_247.gif]

[Graphics:../Images/ContourIntegralMod_gr_248.gif]

[Graphics:../Images/ContourIntegralMod_gr_249.gif]

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2006 John H. Mathews, Russell W. Howell