7 (g).  Evaluate  [Graphics:Images/ContourIntegralModHome_gr_501.gif],   where C is the upper half of  [Graphics:Images/ContourIntegralModHome_gr_502.gif].  

Solution 7 (g).

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/ContourIntegralModHome_gr_503.gif].  

                         [Graphics:../Images/ContourIntegralModHome_gr_504.gif]

                    The contour   [Graphics:../Images/ContourIntegralModHome_gr_505.gif]   for   [Graphics:../Images/ContourIntegralModHome_gr_506.gif].

Solution.  The function is  [Graphics:../Images/ContourIntegralModHome_gr_507.gif]  and the curve is  [Graphics:../Images/ContourIntegralModHome_gr_508.gif]  for  [Graphics:../Images/ContourIntegralModHome_gr_509.gif]  and we obtain

                    [Graphics:../Images/ContourIntegralModHome_gr_510.gif]  and  [Graphics:../Images/ContourIntegralModHome_gr_511.gif],  
                    
                    then

                     [Graphics:../Images/ContourIntegralModHome_gr_512.gif]  

The last two real integrals are computed using

                    [Graphics:../Images/ContourIntegralModHome_gr_513.gif]  

                    and

                    [Graphics:../Images/ContourIntegralModHome_gr_514.gif]  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell