Exercise 17.  Evaluate  [Graphics:Images/ContourIntegralModHome_gr_739.gif],  where C is the polygonal path from [Graphics:Images/ContourIntegralModHome_gr_740.gif] that consists of the
line segments from  [Graphics:Images/ContourIntegralModHome_gr_741.gif]  and [Graphics:Images/ContourIntegralModHome_gr_742.gif].  

Solution 17.

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/ContourIntegralModHome_gr_743.gif].  

Solution.  Use the polygonal path from  [Graphics:../Images/ContourIntegralModHome_gr_744.gif].   

Set up the parameterizations and compute the contour integral.

The function is   [Graphics:../Images/ContourIntegralModHome_gr_745.gif]   and the contour segments are   [Graphics:../Images/ContourIntegralModHome_gr_746.gif].

Find a parameterization of the polygonal path  [Graphics:../Images/ContourIntegralModHome_gr_747.gif]  from  [Graphics:../Images/ContourIntegralModHome_gr_748.gif]  consisting of the two line segments:

                    [Graphics:../Images/ContourIntegralModHome_gr_749.gif]

                    The curve  [Graphics:../Images/ContourIntegralModHome_gr_750.gif]  for  [Graphics:../Images/ContourIntegralModHome_gr_751.gif].  

                    [Graphics:../Images/ContourIntegralModHome_gr_752.gif]

                    The curve  [Graphics:../Images/ContourIntegralModHome_gr_753.gif]  for  [Graphics:../Images/ContourIntegralModHome_gr_754.gif].  

 

                      [Graphics:../Images/ContourIntegralModHome_gr_755.gif]

                    The contour  [Graphics:../Images/ContourIntegralModHome_gr_756.gif].  

                    Where  [Graphics:../Images/ContourIntegralModHome_gr_757.gif]  for  [Graphics:../Images/ContourIntegralModHome_gr_758.gif],  and
                                [Graphics:../Images/ContourIntegralModHome_gr_759.gif]  for  [Graphics:../Images/ContourIntegralModHome_gr_760.gif].    

Part (i).  A parameterization of the line segment [Graphics:../Images/ContourIntegralModHome_gr_761.gif] from   [Graphics:../Images/ContourIntegralModHome_gr_762.gif],  is

                    [Graphics:../Images/ContourIntegralModHome_gr_763.gif],   for   [Graphics:../Images/ContourIntegralModHome_gr_764.gif],   and
                    
                    [Graphics:../Images/ContourIntegralModHome_gr_765.gif],  
                    [Graphics:../Images/ContourIntegralModHome_gr_766.gif].  

Along  [Graphics:../Images/ContourIntegralModHome_gr_767.gif]  we obtain  

                    [Graphics:../Images/ContourIntegralModHome_gr_768.gif]  

Part (ii).  A parameterization of the line segment [Graphics:../Images/ContourIntegralModHome_gr_769.gif] from   [Graphics:../Images/ContourIntegralModHome_gr_770.gif],  is

                    [Graphics:../Images/ContourIntegralModHome_gr_771.gif],   for   [Graphics:../Images/ContourIntegralModHome_gr_772.gif],   and
                    
                    [Graphics:../Images/ContourIntegralModHome_gr_773.gif],  
                    [Graphics:../Images/ContourIntegralModHome_gr_774.gif].  

Along  [Graphics:../Images/ContourIntegralModHome_gr_775.gif]  we obtain  

                    [Graphics:../Images/ContourIntegralModHome_gr_776.gif]

The function is   [Graphics:../Images/ContourIntegralModHome_gr_777.gif]   

and we add the contributions on the contour segments  [Graphics:../Images/ContourIntegralModHome_gr_778.gif]  and get

                     [Graphics:../Images/ContourIntegralModHome_gr_779.gif]  

Aside.  After we have developed the Cauchy-Goursat Theorem in Section 6.3 and the Fundamental Theorem of Calculus in Section 6.4

we will be able to compute the integral in an easy fashion:

                   [Graphics:../Images/ContourIntegralModHome_gr_780.gif].  

We are really done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ContourIntegralModHome_gr_781.gif]

[Graphics:../Images/ContourIntegralModHome_gr_782.gif]



[Graphics:../Images/ContourIntegralModHome_gr_783.gif]

[Graphics:../Images/ContourIntegralModHome_gr_784.gif]

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 



This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell