Exercise 2. Find
the function
that
is harmonic in the sector
and
has the boundary values
![[Graphics:Images/DirichletProblemModHome_gr_41.gif]](../Images/DirichletProblemModHome_gr_41.gif)
Solution 2.
See text and/or instructor's solution manual.
Answer.
.
Solution. Applying
Example 11.2 we know that the form of the solution is
.
Use the values
, and
and
write the system of equations
![]()
.
Simplify them and obtain
, and
.
Solving we get
and
the desired solution
Therefore,
.
We are done.
Aside. We can let Mathematica double check our work.
Aside. If you
prefer to use the function Arg, then
the solution can be written in the form
.
Aside. If
polar coordinates
are
used, then the polar form of the solution
is
.
We are really done.
Aside. For
illustration purposes we can graph the
function
.
![[Graphics:../Images/DirichletProblemModHome_gr_63.gif]](../Images/DirichletProblemModHome_gr_63.gif)
A
contour graph of the function ![]()
where
for
.
We are really really done.
![[Graphics:../Images/DirichletProblemModHome_gr_67.gif]](../Images/DirichletProblemModHome_gr_67.gif)
A
contour graph of the function ![]()
where
for
.
![[Graphics:../Images/DirichletProblemModHome_gr_71.gif]](../Images/DirichletProblemModHome_gr_71.gif)
A
graph of the function
![[Graphics:../Images/DirichletProblemModHome_gr_73.gif]](../Images/DirichletProblemModHome_gr_73.gif)
![[Graphics:../Images/DirichletProblemModHome_gr_74.gif]](../Images/DirichletProblemModHome_gr_74.gif)
A
graph of the function
![[Graphics:../Images/DirichletProblemModHome_gr_76.gif]](../Images/DirichletProblemModHome_gr_76.gif)
![[Graphics:../Images/DirichletProblemModHome_gr_77.gif]](../Images/DirichletProblemModHome_gr_77.gif)
A
graph of the function
![[Graphics:../Images/DirichletProblemModHome_gr_79.gif]](../Images/DirichletProblemModHome_gr_79.gif)
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell